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horsena [70]
3 years ago
15

How do we use light in space?

Physics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

They use LED lights.

Explanation:

Hope this helps

-A Helping Friend (mark brainliest pls)

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The Iceberg Kid, infamous for imposing a deep freeze on whoever disagrees with him, discovers that in his advanced teenaged year
Mademuasel [1]

Answer:

7.24 Ω

Explanation:

Power = energy / time = 195 J / 9.81 = 19.88 W

and power = V² / R

R  resistance = 12 V²  / 19.88 W  = 7.24 Ω

8 0
2 years ago
Given a force of 100 N and an acceleration of 10 m/s2, what is the mass?
Drupady [299]
F=ma, so 100=m×10. Solve for m by dividing by 10. The mass is 10 kg.
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3 years ago
A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is
Vikki [24]

Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

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2 years ago
When a snowball turns into a puddle of
In-s [12.5K]

When a snowball turns into a puddle of water, we know that (the snow ball gains energy and changes from a solid to liquid).

This is correct due to the fact that particles of the snowball are gaining speed and so it is heating up, when the solid's temperature reaches the melting point, it will become a liquid.

Therefore, D is the correct answer.

8 0
2 years ago
A 24 kg child slides down a 3.3-m-high playground slide. She starts from rest, and her speed at the bottom is 3.0 m/s.a. What en
Gelneren [198K]

Answer:

(a) Potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

(b) U=668.16\ J

Explanation:

Given:

  • mass of the child, m=24\ kg
  • height of the slide, h=3.3\ m
  • initial velocity of the child at the slide, v_i=0 m.s^{-1}
  • final velocity of the child at the bottom of slide, v_f=3\ m.s^{-1}

(a)

∴The initial potential energy of the child is converted into the kinetic energy at the bottom off the slide and a part of which is lost into friction generating heat between the contact surfaces.

Initial potential energy:

PE=m.g.h

PE=24\times 9.8\times 3.3

PE=776.16\ J

Kinetic energy at the bottom of the slide:

KE=\frac{1}{2} m.v^2

KE= 0.5\times 24\times 3^2

KE= 108\ J

(b)

Now, the difference in the potential and kinetic energy is the total change in the thermal energy of the slide and the seat of her pants.

This can be given as:

U=PE-KE

U=776.16-108

U=668.16\ J

4 0
2 years ago
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