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Bumek [7]
3 years ago
8

What causes short sightedness ?how is it corrected

Physics
1 answer:
7nadin3 [17]3 years ago
5 0

Answer:

Short sight occurs when the eyeball is too long or the lens is too thick, or both. As a result, light rays from distant objects are focused in front of the retina (because the light rays are highly converged). The image formed on the retina is therefore out of focus.

Short sight can be corrected by wearing glasses with concave lenses. Light rays from distant objects are diverged by concave lenses before entering the eyes, so that light can be focused on the retina to form a sharp image.

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Consider the reaction.
BaLLatris [955]

Answer:

Explanation:

Consider the reaction.A(g)↽−−⇀Z(g)A

A

(

g

)

↽

−

−

⇀

Z

(

g

)

The equilibrium constant,

K

, expresses the relationship between the concentrations of the species at equilibrium.

(g)

The energy of A-A bond in A is 98 kJ/mol. The energy of Z-Z bond in Z is 165 kJ/mol. Which statement about the reaction is correct?

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

5) The energy of A-A bond in A is greater than the energy of Z-Z bond in Z.

1) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is smaller than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

It is correct that the activation energy for Reaction ↽−+X(g)AX(g) is smaller than that for Reaction ⇀+AX(g)↽−, because AX is less stable than A or Z, so it takes less energy to break the weaker bond in AX.

2) The amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

3) The amount of energy released when A and Z combine to form AX will be less than the total energy needed to break both A-A and Z-Z bonds.

Option (2) is incorrect because, though the formation of AX requires energy, which is not needed for the formation of A or Z; however, the total energy required to break both A-A and Z-Z bonds (above) is more than the amount released when A and Z combine to form AX.

Option (3) is incorrect because the amount of energy released when A and Z combine to form AX will be greater than the total energy needed to break both A-A and Z-Z bonds (above).

4) The activation energy for the forward reaction, Reaction ↽−+X(g)AX(g), is greater than the activation energy for the reverse reaction, Reaction ⇀+AX(g)↽−.

8 0
3 years ago
In a softball game, a batter hits the ball at the velocity and angle shown
Kipish [7]
This problem is going to be pretty long to solve. So, prepare.

We’re interested in the change in our x position. So we have to break the velocity vector up into its components. Do cosine of 50 and then multiply by the magnitude of the velocity. I got 20.57m/s. That’s our initial velocity. And remember, horizontal acceleration is zero. The vertical acceleration, or any vertical component, has no effect on the horizontal components. In order to solve this problem, we want to utilize this equation:
Change in x-position = Vix*t

Let’s solve for time, which is dependent on the vertical components. The projectile will stop when it vertically hits the ground. Generally you want to use this equation for solving for time:
Yf = Yi + Viy*t + 1/2at^2
We didn’t solve for the vertical component yet, so let’s do that now. (Sine of 50)*(32) = 24.51m/s
Let’s now plug everything in:
0 = 0 + 24.5t - 4.9t^2
0 = 24.5t - 4.9t^2
0 = t(24.5 - 4.9t)
-24.5 = -4.9t
t = 5 seconds

The hard stuff is pretty much over. Put that 5 seconds into the other equation I said we wanted to use to solve the problem
Change in x-position (range) = (20.57)*(5)
= 102.85 meters

Answer B
5 0
4 years ago
What changes dead plants and animals into ammonia compounds?
lapo4ka [179]

Nitrogen fixing bacteria changes dead plants and animals into ammonia compounds.

<h2>What is nitrogen fixation?</h2>

Atmospheric nitrogen is converted into nitrogen oxides by the action of lightning, which helps its incorporation into the soil.

<h3>Characteristics of Nitrogen fixing bacteria</h3>

  • Nitrogen is fixed by these bacteria and other prokaryotes through various metabolic processes, which convert it into different usable compounds, such as ammonia (NH3) and ammonium ion (NH4+).

  • These microorganisms can be found in soil and water, or as plant symbionts.

Therefore, we can conclude that nitrogen fixing bacteria fix nitrogen from the air, that is, they originate soluble compounds by plants, such as ammonia.

Learn more about nitrogen fixation here: brainly.com/question/14726009

7 0
2 years ago
I need help ;-;
Mkey [24]
The First Quarter Moon is a primary Moon phase when we can see exactly half of the Moon's visible surface illuminated. If it is the left or right half, depends on where you are on Earth.
8 0
3 years ago
Read 2 more answers
Identical isolated conducting spheres 1 and 2 have equal charges and are separated by a distance that is large compared with the
scoundrel [369]

Answer:

F = 0.1575 N

Explanation:

When the third sphere touches the first sphere, the charge is distributed between both spheres, then now the first sphere has only half of his original charge.

In this moment then

Sphere one has a charge = Q/2

Sphere three has a charge = Q/2

Now when the third sphere touches the second sphere again the charge is distributed in a manner that both sphere has the same charge.

How the total charge is Q = Q/2 + Q = 3/2Q, when the spheres are separated each one has 3/4Q

Sphere two has a charge = 3/4Q

Sphere three has a charge = 3/4Q

The electrostatic force that acts on sphere 2 due to sphere 1 is:

F = \frac{kQ_{1}Q_{2} }{r^{2} }

F= \frac{K(Q/2)(3Q/4)}{r^{2} }

how \frac{KQ^{2} }{r^{2} } = 0.42

Then

F = \frac{0.42*3}{8}

F = 0.1575 N

3 0
3 years ago
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