Acceleration = (change in speed) / (time for the change).
Change in speed = (15 - 30) = -15 km/hr
Time for the change = 4 sec
Acceleration = (-15 km/hr) / (4 sec) = -3.75 km/hr per second .
Is that a lot ? Not much ?
Let's convert it to a unit that we can think about:
(-15 km/hr) x (1,000 m/km) x (1 hr / 3,600 sec) =
(-15 x 1,000) / (3,600) = -(4 and 1/6) m/sec .
So the acceleration of the bus is -(4 and 1/6) m/sec² .
The negative sign means that it slowed down.
(4 and 1/6) m/sec² is about 42% of the acceleration of gravity ...
the acceleration the bus would have if it drove off of a cliff.
When the car or the bus you're riding in slows down at that rate,
you feel 42% of your weight pulling you forward against your
seat belt. That's quite a drastic acceleration !
Answer:
The maximum induced emf is 15.08 V
Explanation:
Given;
number of turns of the generator, N = 6 turns
area of the loop, A = 0.04 m
magnetic field of the loop, B = 0.2 T
frequency of loop, f = 50 Hz
The maximum induced emf is given by;
E = NBAω
Where;
ω is the angular speed = 2πf
E = NBA(2πf)
E = 6 x 0.2 x 0.04 x (2 x 3.142 x 50)
E = 15.08 V
Therefore, the maximum induced emf is 15.08 V
D A little longer than a yard (about 3 ft)
Answer:
I believe that its B my apologies if its wrong/
Explanation:
Answer:
4.3 m/sec
Explanation:
Here height of cliff = y = 37.6 m
Gravitational acceleration = g = 9.8 m/sec2
vi = 0 m/s
Let's find the time which the diver will take if jumps from there!
Using formula
y = vit+1/2gt2
==> 37.6= 0 + 0.5 ×9.8×
==>= 
==> t = 2.8 sec
In this time the diver has to cover a horizontal distance of 12.12 m
If x = 12.12 m is the horizontal distance to be covered then using
x= Vx × t
==> Vx = x/t
==> Vx= 12.12/2.8 = 4.3 m/s
