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2 years ago

The layers in a high-mass star occur in order of:________

Physics

1 answer:

zavuch27 [327]2 years ago

6 0

A high-mass star has layers that are arranged in order of b. Temperature for fusion.

<h3>What is the temperature of fusion?</h3>

The temperature at which a substance transforms from a solid to a liquid is known as its melting point. The solid and liquid phases are in equilibrium at the melting point. Pressure affects a substance's melting point, which is typically reported at a standard pressure such 1 atmosphere or 100 kPa. There are two main categories of fusion reactions: those that maintain the ratio of protons to neutrons and those that convert protons to neutrons. The solid-liquid and liquid-to-gas transitions are connected with the typical heats of fusion and vaporization, respectively, for each substance.

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Complete Question

A football coach walks 18 meters westward, then 12 meters eastward, then 28 meters westward, and finally 14 meters eastward.

From this motion what is the distance covered

What is the magnitude and direction of the displacement

Answer:

$D = 72 \ m$

Magnitude

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Direction

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Explanation:

From the question we are told that

The first distance covered westward is $d_w_1 = 18 \ m /tex] The first distance covered eastward is [tex]d_e1 = 12 \ m /tex] The second distance covered westward is [tex]d_w_2 = 28 \ m /tex] The second distance covered eastward is [tex]d_e2 = 14 \ m /tex] Generally the distance covered is mathematically represented as [tex]D = d_w1 + d_w2 + d_e1 + d_e2$

=> $D = 18 + 28 + 12 + 14$

=> $D = 72 \ m$

For the second question eastward is in the direction of the positive x-axis so it would be positive and westward is in the direction of the negative x-axis so it would be negative

The magnitude of the displacement is

$d = -d_w1 -d_w2 + d_e1 + d_e2$

=> $d = -18-28 + 12 + 14$

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3 years ago

If the Sun suddenly went dark, we would not know it until its light stopped arriving on Earth. How long would that be, in second

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Answer: 500 s

Explanation:

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$v=\frac{d}{t}$

Where:

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$d=1.5(10)^{11}m$ is the distance between the Earth and Sun

$t$ is the time it takes to the light to travel the distance $d$

Isolating $t$ :

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$t=\frac{1.5(10)^{11}m}{3(10)^{8}m/s}$

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