Question

How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Answer 1

 a =  ( V2 - V1)/( t2 - t1)
 3.2 =  ( 23.5m/s - 15.2m/s)/(t - 0)
3.2m/s = 8.3/t
t(3.2) = 8.3
t = 8.3/3.2
t = 2.59 seconds

Answer 2

Hello!

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?

We have the following data:

Vf (final velocity) = 23.5 m/s

Vi (initial velocity) = 15.2 m/s

ΔV  (speed interval)  = Vf - Vi → ΔV  = 23.5 - 15.2 → ΔV  = 8.3 m/s

ΔT (time interval) = ? (in s)

a (average acceleration) = 3.2 m/s²

Formula:

$a = \dfrac{\Delta{V}}{\Delta{T^}}$

Solving:  

$a = \dfrac{\Delta{V}}{\Delta{T^}}$

$3.2 = \dfrac{8.3}{\Delta{T^}}$

$\Delta{T^} = \dfrac{8.3}{3.2}$

$\Delta{T^} = 2.59375 \to \boxed{\boxed{\Delta{T^} \approx 2.6\:s}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:  

The car will take approximately 2.6 seconds to accelerate

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I Hope this helps, greetings ... Dexteright02! =)