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KiRa [710]
3 years ago
11

There are 2.2 pounds in a kilogram. if a boys mass is 40kg, what is his height in pounds?

Physics
2 answers:
Lera25 [3.4K]3 years ago
4 0
There are NOT 2.2 pounds in a kilogram. 
Any teacher who makes such a statement is misleading you, and
putting things into your head that will be tough to get rid of later.

2.2 pounds is the approximate WEIGHT of 1 kilogram of MASS
on Earth.  The SAME KILOGRAM of mass weighs about 5.8 ounces
on the Moon, and about 11.8 ounces on Mars.

If a boy's mass is 40 kg, then he weighs about 29.2 pounds on Mars,
about 14.7 pounds on the Moon, and about 89 pounds on Earth.

"Height" doesn't belong anywhere in this question.
sasho [114]3 years ago
3 0
The simplest way to do this is to set up equivalent fractions, like this- 

\frac{1}{2.2} = \frac{40}{x}

Solve for x by using cross multiplication.

40*2.2= 88
1*x=88
x=88

Therefore, the boy weighs 88lbs. 
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Atoms that have become negatively charged by gaining extra electrons are called _____. anions anodes cations cathodes
nikklg [1K]
Anions: negatively charged atoms

Cations: positively charged atoms (CAT-ions are PAWS-itively charged)
Anode: positively charged electrode that allows electrical current flow (positive end of battery)
Cathode: negatively charged electrode that allows electrical current flow (negative end of batter)
5 0
3 years ago
Read 2 more answers
Calculate the volume of this regular solid. A cone 4.5 centimeters high with a radius of 3 centimeters. Label B is pointing to t
Greeley [361]

Answer:42.41

Explanation:

5 0
3 years ago
Your pet hamster sits on a record player whose angular speed is constant. If he moves to a point twice as far from the center, t
3241004551 [841]

Answer:

option A

Explanation:

given,                    

angular speed is constant

initial distance = r                

final distance (r')= 2 r

initial linear velocity = v

final linear velocity = v'

we know,                  

v = r ω......................(1)

where r is the distance

ω is the angular speed

now,            

v' = r' ω            

v' = 2 r ω        

v' = 2 v                

hence, the linear velocity doubles.

The correct answer is option A

3 0
3 years ago
How high will a 0.345 kg rock go if thrown straight up by someone who does 111 J of work on it? Neglect air resistance.
Eddi Din [679]

To solve this problem we will apply the concepts related to energy conservation. Here we will understand that the potential energy accumulated on the object is equal to the work it has. Therefore the relationship that will allow us to calculate the height will be

W = PE

W = mgh

Here,

m = mass

g = Acceleration due to gravity

h = Height

our values are,

m = 0.345 kg

g = 9.8m/s^2

W = 111J

Replacing,

W =mgh

111 = (0.345)(9.8)h

h = 32.83m

Then the height is 32.83m.

7 0
3 years ago
Pls help me with this question​
ryzh [129]

Answer:

16 ms2 is the answer for this question

8 0
3 years ago
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