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3 years ago

According to the Theory of Plate Tectonics, which of the following statements is correct?

Physics

1 answer:

kramer3 years ago

8 0

Answer:

It's D. The geothermal energy from Earth's core loses most of its heat before reaching the outer layer. The plates on the outer layer have been proven to be moving due to evidence such as earthquakes, volcanic eruptions, and tsunamis.

Explanation:

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I need help asap pls

tigry1 [53]

no.9 indeed all matters are made out of atoms which is smaller than protons and neutrons

6 0

3 years ago

A 0.200-kg cube of ice (frozen water) is floating in glycerine.The gylcerine is in a tall cylinder that has inside radius 3.90 c

natita [175]

Answer:

Part a)

h = 0.86 cm

Part b)

Level will increase

Explanation:

Part a)

Mass of the ice cube is 0.200 kg

Now from the buoyancy force formula we know that weight of the ice is counter balanced by buoyancy force on the ice

So here we will have

$mg = \rho V_{displaced} g$

$V_{displaced} = \frac{m}{\rho}$

$V_{displaced} = \frac{0.200}{1260} = 1.59 \times 10^{-4} m^3$

now as we know that ice will melt into water

so here volume of water that will convert due to melting of ice is given as

$V\rho_w = m_{ice}$

$V = \frac{0.200}{1000} = 2\times 10^{-4} m^3$

So here extra volume that rise in the level will be given as

$\Dleta V = V - V_{displaced}$

$\pi r^2 h = 2\times 10^{-4} - 1.59 \times 10^{-4}$

$(\pi (0.039^2) h = 0.41 \times 10^{-4}$

$h = 0.86 cm$

Part b)

Since volume of water that formed here is more than the volume that is displaced by the ice so we can say that level of liquid in the cylinder will increase due to melting of ice

5 0

3 years ago

Which muscle is the main muscle of mastication?

Valentin [98]

Answer: Masseter muscle

Explanation:

The masseter muscle is the most powerful muscle of mastication. It is quadrangular in shape and has two parts: deep and superficial. The entirety of the muscle lies superficially to the pterygoids and temporalis, covering them.

4 0

3 years ago

A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3300

adell [148]

Answer:

v = 306.76 Km/h

Explanation:

given,

height of the aircraft = 3000 m

differential pressure reading = 3300 N/m²

density of air = 0.909 Kg/m³

speed of aircraft = ?

Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.

using Bernoulli's equation

$\dfrac{v^2}{2} = \dfrac{\Delta P}{\rho}$

where ρ is the density of the air at 3000 m

$v= \sqrt{\dfrac{2 \times \Delta P}{\rho}}$

$v= \sqrt{\dfrac{2 \times 3300}{0.909}}$

$v = \sqrt{7260.726}$

v = 85.21 m/s

$v= 85.21 \times \dfrac{3600}{1000}$

v = 306.76 Km/h

4 0

3 years ago

Why would an asteroid have a difficult time of holding a probe or person?

babymother [125]

The asteroid's mass is so small that it has a much smaller acceleration
due to gravity than Earth has. That means that things weigh very very little
on the surface of an asteroid. It also means that the "escape velocity" from
an asteroid is very low, and orbital velocities are very low at any distance off
of its surface.

As an extreme example: You know how when you walk, you naturally rise up
on the toes of one foot while you reach out with the other one to take a step ?
All of those motions are what you learn in Earth's gravity. On an asteroid, that
natural action of rising up on your toes might launch you into a long, high arc,
like a golf ball. Or it might even exceed escape velocity and you'd sail up off
of the asteroid and never come back down to it.

5 0

3 years ago