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2 years ago

5. He slept for eight hours. This sentence has

Physics

2 answers:

Galina-37 [17]2 years ago

7 0

Answer:

an object (it's English

Alisiya [41]2 years ago

6 0

An object ( it’s english )

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A roller coaster car of mass m= 300 kg is released from rest at the top of a 60 m high hill (position A), and rolls with a negli

Andrews [41]

Answer: The principle of conservation of energy, angular speed and centripetal force

Explanation:

At point A, the car experienced maximum of potential energy

As it moves down the hill, the potential energy decreases while the kinetic energy increases.

The maximum kinetic energy of the car is needed for the attainment of enough centripetal force to help the car move through the loop without falling .

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2 years ago

A NASA explorer spacecraft with a mass of 1,000 kg takes off in a positive direction from a stationary asteroid. If the velocity

Jet001 [13]

Before the launch, the momentum of the (spacecraft + asteroid) was zero. So after the launch, the momentum of the (spacecraft + asteroid) has to be zero.

Momentum = (mass) x (velocity)

Momentum after the launch:

Spacecraft: (1,000 kg) x (250 m/s) = 250,000 kg-m/s

Asteroid: (mass) x (-25 m/s)

Their sum: 250,000 - 25(mass) .

Their sum must be zero, so 250,000 kg-m/s = (25 m/s) x (mass)

Divide each side by 25 : 10,000 kg-m/s = (1 m/s) x (mass)

Divide each side by (1 m/s) : 10,000 kg = mass

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2 years ago

Read 2 more answers

A 35 g steel ball is held by a ceiling-mounted electromagnet 3.8 m above the floor. A compressed-air cannon sits on the floor, 4

n200080 [17]

Answer:

Explanation:

Let v is the launch speed of the plastic ball and the angle of projection is θ.

So, in horizontal direction

v Cosθ x t = 4.8 .... (1)

In th evertical direction

1.4 = v Sin θ x t - 0.5 gt² .... (2)

As , v Sin θ x t = 3.8 .... (3) , put in equation (2)

1.4 = 3.8 - 4.9 t²

t = 0.7 s

Put in (1) and (3)

v Cosθ x 0.7 = 4.8

v Cosθ = 6.86

and v Sinθ x 0.7 = 3.8

v Sinθ = 5.43

Now

$v^{2}\left ( Sin^{2}\theta +Cos^{2}\theta \right )=5.43^{2}+6.86^{2}$

v = 8.75 m/s

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2 years ago

A chemical reaction is the only way to an

Klio2033 [76]

Answer:

B: Pure Substance

Explanation:

7 0

2 years ago

An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled duri

Orlov [11]

Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is $13m/s^2$ .

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

$s=ut+\frac{1}{2}at^2$

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

$s=0\times5+\frac{1}{2}\times13\times 5^2$

$s=0+\frac{1}{2}\times13\times 25$

$s=0+\frac{1}{2}\times325$

s = 162.5 m

Therefore, distance traveled is 162.5 m.

3 0

2 years ago