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Varvara68 [4.7K]
4 years ago
12

Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12.6 g and a m

easured side length of 4.1 cm? (Density: D = )
Chemistry
1 answer:
AysviL [449]4 years ago
6 0

Answer:

0.1828g/cm³

Explanation:

density= mass÷volume

m= 12.6g

v= 4.1×4.1×4.1 = 68.921cm³

•

density= 12.6÷68.921 = 0.1828g/cm³

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In the lewis formula for sulfur dioxide, so2, the number of lone pairs of electrons around the sulfur atom is?
Nastasia [14]

The molecule of sulfur dioxide has two pi and two sigma bonds and one lone pair of electrons.

<h3>What is lone pair?</h3>
  • A lone pair, also known as an unshared pair or a non-bonding pair, is an unshared pair of valence electrons that are not shared with another atom in a covalent connection in chemistry.
  • Atom's outermost electron shell contains lone pairs. The Lewis structure can be used to locate them.
  • Due to the high electric charge of a lone pair, which results in strong electron repulsion, the bond angle between the bonding pair of electrons reduces.
  • They participate in the creation of a dative relationship as well.

Learn more about lone pair here:

brainly.com/question/15182074

#SPJ4

5 0
2 years ago
What would be the mass of gas inside a 3.0-L balloon at 0 degrees Celsius and 1.0 atm filled with carbon dioxide gas? *
Anni [7]

Answer:

5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide gas = 1.0 atm

V = Volume of carbon dioxide gas = 3.0 L

n = number of moles of carbon dioxide gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of carbon dioxide gas =0°C = 0+273= 273 K

Putting values in above equation, we get:

(1.0 atm)\times 3.0 L=n\times (0.0821L.atm/mol.K)\times 273 K\\\\n=0.13 mol

Mass of 0.13 mole carbon dioxide gas :

= 0.13 mol × 44 g/mol = 5.7 g

5.7 grams is the mass carbon dioxide gas inside a 3.0-L balloon.

3 0
3 years ago
Calculate the pOH of an aqueous solution of .0.073 M LiOH
Novosadov [1.4K]

Considering the definition of pOH and strong base, the pOH of the aqueous solution is 1.14

The pOH (or potential OH) is a measure of the basicity or alkalinity of a solution and indicates the concentration of ion hydroxide (OH-).

pOH is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

On the other hand, a strong base is that base that in an aqueous solution completely dissociates between the cation and OH-.

LiOH is a strong base, so the concentration of the hydroxide will be equal to the concentration of OH-. This is:

[LiOH]= [OH-]= 0.073 M

Replacing in the definition of pOH:

pOH= -log (0.073 M)

<u><em>pOH= 1.14 </em></u>

In summary, the pOH of the aqueous solution is 1.14

Learn more:

  • <u>brainly.com/question/16032912?referrer=searchResults </u>
  • <u>brainly.com/question/13557815?referrer=searchResults</u>
7 0
3 years ago
Which elements are gases at STP?
Gwar [14]

Answer:

hydrogen (H), nitogen (N), oxygen (O), fluorine (F), chlorine (Cl), helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), radon (Rn)

Explanation: found this online, it's best to remember them.

7 0
3 years ago
A flask contains 0.83molof neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the
blsea [12.9K]

Answer:

V = 56.72 L

Explanation:

Given data:

Number of mole of neon gas = 0.83 mol

Temperature = 35°C

Pressure = 0.37 atm

Volume of gas = ?

Solution;

Temperature = 35°C  (35+273 =308K)

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

Now we will put the values in formula.

V = nRT/P

V = 0.83 mol ×0.0821 atm.L/mol.K ×308K / 0.37 atm

V = 20.99 L/  0.37

V = 56.72 L

6 0
3 years ago
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