Hello from MrBillDoesMath!
Answer:
"The factoring should follow the perfect square trinomial pattern"
Discussion:
y^2 - 2(y)(3) + 3^2 =
(y -3
) ^2
not (y-3) (y+3) so the last step shown is incorrect. The answer is "The factoring should follow the perfect square trinomial pattern"
Thank you,
MrB
The following classification of <em>quadratic</em> equations is presented below:
- x = - 2 and x = 3: h(x) = (x + 2) · (x - 3), k(x) = - 3 · (x + 2) · (x - 3).
- x = 2 and x = - 3: g(x) = 8 · (x + 3) · (x - 2), m(x) = (x + 3) · (x - 2).
- Neither: j(x) = (x - 2) · (x - 3)
<h3>How to classify quadratic equations in terms of its roots</h3>
In this problem we have <em>quadratic</em> equations in <em>factored</em> form, whose form is presented below:
y = a · (x - r₁) · (x - r₂) (1)
Where r₁ and r₂ are the roots of the equation and a is the <em>leading</em> coefficient. A value of x is a root if and only if y is zero. Besides, we must located all the <em>quadratic</em> equations according to their roots.
x = - 2 and x = 3
h(x) = (x + 2) · (x - 3)
k(x) = - 3 · (x + 2) · (x - 3)
x = 2 and x = - 3
g(x) = 8 · (x + 3) · (x - 2)
m(x) = (x + 3) · (x - 2)
Neither
f(x) = 3 · (x - 1) · (x + 2)
j(x) = (x - 2) · (x - 3)
To learn more on quadratic equations: brainly.com/question/17177510
#SPJ1
Interquartile range is the range is the number in the dead center, you have to divide the number line into 2 sections. The middle of everything and the middle of both section is the interquartile range
Hope this helps!
Answer:
![\frac{ \sqrt{3} }{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7B3%7D%20)
Step-by-step explanation:
![(sin30 + \cos(60) )( \tan(60) - \sec(30)](https://tex.z-dn.net/?f=%28sin30%20%2B%20%20%5Ccos%2860%29%20%29%28%20%5Ctan%2860%29%20%20-%20%20%5Csec%2830%29%20)
![( \frac{1}{2} + \frac{1}{2} )( \sqrt{3} - \frac{2 \sqrt{3} }{3})](https://tex.z-dn.net/?f=%28%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%29%28%20%5Csqrt%7B3%7D%20-%20%20%5Cfrac%7B2%20%5Csqrt%7B3%7D%20%7D%7B3%7D%29%20%20)
over 3
![= \frac{ \sqrt{3} }{3}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7B3%7D%20)
Answer:
D.5/1
Step-by-step explanation:
5\1 is just 5 in fraction form