So g(x) doesn't come in
ok
remember pemdas
inside first
evaluate f(4)
f(4)=4^2+1=16+1=17
now we have
[17]^2=289
answer s 289
Answer:
It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.
Step-by-step explanation:
Given that:
sample size n = 1600
sample mean
= 20000
standard deviation = 5000
The objective is to choose from the given option about what most closely resembles the relevant box model.
The correct answer is:
It has millions of tickets. On each ticket is written a number a dollar amount. The exact average and SD are unknown but are estimated from the sample to be $20,000 and $5,000 respectively.
However, if draws are made without replacement, the best estimate of the average amount for the bride will be $20,000
Similarly, the standard error for the sample mean = 


the standard error for the sample mean = 125
{(2, 3), (1, 5), (2, 7)} - NOT because 2->3 and 2->7
{(11, 9), (11, 5), (9, 3)} - NOT because 11->9 and 11->5
{(3, 8), (0, 8), (3, -2)}
- NOT because 3->8 and 3->-2
{(-1, 5), (-2, 6), (-3, 7)} - YES
Answer:
14.4 lb
Step-by-step explanation:
In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.
The torque generated by the child is:
T1 = 60 * 3 = 180 lb*feet
So, the torque generated by the weight needs to be higher than T1 in order to lift the child.
The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.
So, we have that:
T2 = 180 = mass * 12.5
mass = 180/12.5 = 14.4 lb
So the lowest weight is 14.4 lb
I’m so sorry but do you have a better picture i can’t see it
The only questions that I can see is 8 and 9
8: B
9: C