The amount of water in the air is humidity .
Answer:
B
Explanation:
CH4 + O2 →H2O + CO2
Left side
C = 1
H = 4
O = 2
Right side
C = 1
H = 2
O = 3
So find common denominator in this case would be 6 O
CH4 + 3O2 →2H2O + CO2
Left side
C = 1
H = 4
O = 6
Right side
C = 1
H = 4
O = 6
A cleaning solution with an OH⁻ concentration of 2.5 × 10⁻⁴ mol/L, has a pH of 10.4 and is basic (options b and c).
<h3>How can we determine the acidity or basicity of a solution?</h3>
- If pH < 7, the solution is acid.
- If pH = 7, the solution is neutral.
- If pH > 7, the solution is basic.
- Step 1. Calculate the pOH of the solution.
The hydroxide ion concentration is 2.5 × 10⁻⁴ mol/L.
pOH = -log [OH⁻] = log (2.5 × 10⁻⁴) = 3.6
- Step 2. Calculate the pH of the solution.
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 - 3.6 = 10.4
Since pH > 7, the solution is basic.
A cleaning solution with an OH⁻ concentration of 2.5 × 10⁻⁴ mol/L, has a pH of 10.4 and is basic (options b and c).
Learn more about pH here: brainly.com/question/172153
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Answer:
0.007 moles of octane
Explanation:
Balanced Equation: 2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
0.065 mol H₂O * 2 mol C₈H₁₈/18 mol H₂O = 0.00722... = 0.007 mol C₈H₁₈
The question is missing the number of moles of carbon dioxide that will react with water.
I will work the problem with an arbitrary amount of carbon dioxide to show how to solve it.
For this, I will take 2.40 moles of carbon dioxide.
Answer:
- <u>The number of moles of oxygen atoms produced is equal to the number of moles of carbon dioixide that react: 2.40 moles of oxygen.</u>
<u></u>
- 2.40 has 3 significant figures.
Explanation:
<u>1) Word equation:</u>
- carbon dioxide gas + liquid water (in the presence of light) → aqueous glucose + oxygen gas
<u>2) Balanced chemical equation</u>
- 6CO₂ (g) + 6H₂O (l) → C₆H₁₂O₆ (aq) + 6O₂(g)
<u>3) Mole ratios</u>
- 6 mol CO₂ (g) : 6 mol H₂O (l) : 1 mol C₆H₁₂O₆ (aq) : 6 mol O₂(g)
<u>4) Set a proportion:</u>
It is assumed that there is plenty liquid water (excess reactant), so you can set a proportion with the number of moles of carbon dioxide:
- 6 mol CO₂ / 6 mol O₂ = 2.40 mol CO₂ / x
From which, x = 2.40 mol O₂
So, the number of moles of oxygen produced is equal to the number of moles of carbon dioxide that react.
Since the number of moles of reactant has 3 significant figures, and the stoichiometric coefficients are considered exact, the answer also has 3 significant figures.
