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zzz [600]
2 years ago
10

What is the movement of water up a narrow tube due to attractions with the surface of the tube called? capillary action meniscus

polarity surface tension.
Chemistry
1 answer:
Shtirlitz [24]2 years ago
6 0

The attraction mediated flow of water in the narrow tube has been termed as Capillary action. Thus, option A is correct.

The process of flowing up of liquid with the attraction force between the molecules and the surface has been achieved with the surface characteristics.

<h3>Movement of water in a narrow tube</h3>

The surface has the force of attraction with the flowing liquids in the sample. It results in the increased surface interaction, and the liquid flows up in the tube against gravity.

The movement of the liquid in the water through a narrow tube has been termed as capillary action. Thus, option A is correct.

Learn more about movement of water, here:

brainly.com/question/1295312

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<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. NH_{3}

<h2>Why?</h2>

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

MolecularFormula=n(EmpiricalFormula)

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. N_{2}O_{4}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

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B. NH_{3}

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. C_{3}H_{6}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

C_{3}H_{6}=3(CH_{2})

D. P_{4}O_{10}

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

P_{4}O_{10}=2(P_{2}O_{5})

Hence, the empirical formula is the option B. NH_{3}

Have a nice day!

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