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Strike441 [17]
3 years ago
12

A temperature of 37°C is equivalent to a temperature of

Chemistry
1 answer:
STatiana [176]3 years ago
7 0
0K = -273C
So
273K = 0C
And
310K = 37C
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A girl throws a rock into a pond. A leaf floating on the pond bobs up and down but does not change location on the pond's surfac
sertanlavr [38]

This is due to the difference in density. The rock is denser than the leaf. And also, the rock is denser than the liquid in the pond. If the material is denser than the other material, it will sink. The same holds true for the rock, it sinks. But when the material is less dense than the other material, it floats. And it holds true for the leaf, it floats.

6 0
4 years ago
If you pour water into a hot metal pan, the water will absorb heat energy from the pan. Will the water come to the same temperat
Marina CMI [18]

Answer:

Yes

Explanation:

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3 years ago
How much milk at 1 degrees Celsius is needed to reduce the temperature of
Kobotan [32]
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3 years ago
The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g
ra1l [238]

Answer:

1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.

Explanation:

1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

6.97g.\frac{1mol}{22.98g} .\frac{-369kJ}{2mol} =-56.0kJ

2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).

CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g)  ΔH = 2.80 kJ

The enthalpy of the reaction is positive, which means that 2.80 kJ of energy are absorbed per mole of carbon monoxide. The energy evolved for 10.4 g of CO (molar mass 28.01 g/mol) is:

10.4g.\frac{1mol}{28.01g} .\frac{2.80kJ}{mol} =1.04kJ

3 0
4 years ago
Calculate the molar mass of carbon tetrafluoride (CF4) in grams per mole, rounding to proper significant figures, if mc= 12.01 u
Nata [24]

Answer:

molar mass of carbon tetrafluoride (CF4) is

(12.01 × 1 ) + ( 4 × 19.00)

= 12.01 + 76

= 88.01u

= 88u

Hope this helps

3 0
3 years ago
Read 2 more answers
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