Alkynes can be reduced to<span> trans</span>-alkenes using Li(lithium) in NH₃(ammonia).
<span>Lithium is a reducing agent.
In this case product is trans-2-butene.
Reaction:
CH</span>₃<span>-C≡C-CH</span>₃ (2-butyne)<span> + 2 Li in N<span>H</span></span>₃<span> (liq) ——>
trans CH</span>₃<span>-CH=CH-CH</span>₃<span> + 2 LiN<span>H</span></span>₂ (lithium-amide).<span><span><span>
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The balanced chemical equation for reaction of and is as follows:
From the balanced chemical equation, 2 mol of reacts with 1 mol of .
First calculating number of moles of as follows:
On rearranging,
Here, M is molarity and V is volume. The molarity of is given 0.274 M or mol/L and volume 155 mL, putting the values,
Since, 1 mol of reacts with 2 mol of thus, number of moles of will be .
Now, molarity of is given 0.305 M or mol/L thus, volume can be calculated as follows:
Therefore, volume of is 278.5 mL.
Answer:
until it gets bright white or smells bad, then throw it out
Explanation:
use variable
1K₂MnF₆ + aSbF₅⇒ bKSbF₆ + cMnF₃ + dF₂
K, left=2,right=b⇒b=2
Mn, left=1, right=c⇒c=1
Sb, left=a, right=b⇒a=b=2
F, left=6.1+5a, right=6b+3c+2d
equation:
6+5(2) = 6(2)+3(1)+2d
16=15+2d
1=2d
d=0.5
So the reaction equation becomes:
1K₂MnF₆ + 2SbF₅⇒ 2KSbF₆ + 1MnF₃ + 0.5F₂ x2
2K₂MnF₆ + 4SbF₅⇒ 4KSbF₆ + 2MnF₃ + F₂
<span>How does the modern Periodic Table of the Elements differ from Mendeleev's chart?</span>
Dmitri Mendeleev's periodic table<span> featured </span>elements<span> arranged in accordance with their atomic mass, while the </span>modern table<span> has </span>elements<span> arranged according to </span>periodic<span> number. </span>Mendeleev's periodic table<span> also had the </span>elements<span> arranged vertically, whereas the </span>modern table<span> has them arranged horizontally.
Hope This Helped! :3
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