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3 years ago

A long straight wire carries a current of 51.7 A. An electron, traveling at 7.43 × 10^7 m/s, is 5.76 cm from the wire.

Physics

1 answer:

eduard3 years ago

3 0

Answer:

(a) 2.13*10^{-5} N

(b) 2.13*10^{-5} N

Explanation:

the magnitude of the magnetic field generated by the wire is:

$\frac{\mu_0I}{2\pi r}=\frac{(4\pi*10^{-7})(51.7A)}{2\pi(5.76*10^{-2}m)}=1.79*10^{-4}T$

if we assume that the current is in the +y direction, B is in the +z direction.

(a) toward the wire, electron is in the -x direction. The angle between B and v is 90°. By using the following formula we obtain:

$F_1=qvBsin90\°=(1.6*10^{-19}C)(7.43*10^{7}\frac{m}{s})(1.79*10^{-4}T)=2.13*10^{-15}N$

(b) parallel to the wire, electron is in the +y direction. Again angle between B ans v is 90°.

$F_2=qvB=2.13*10^{-15}N$

(c) perpendicular to both previous directions, that is, +z or -z. In this case velocity vector is parallel to the magnetic field vector. Hence:

F3=0N

hope this helps!

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How much work in J does the string do on the boy if the boy stands still?

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How much work does the string do on the boy if the boy walks a horizontal distance of 11m away from the kite? 

answer: might be a trick question since his direction away from the kite and his velocity weren't noted. Perhaps he just set the string down and walked away 11m from the kite. If he did this, it is the same as the first one...no work was done by the sting on the boy. 

If he did walk backwards with no velocity indicated, and held the string and it stayed at 30 deg the answer would be: 
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work = total force1 x 11 meters 
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How much work does the string do on the boy if the boy walks a horizontal distance of 11m toward the kite? 

answer: same as above only reversed: 
4.5N - (boys negative acceleration * mass) = total force2 
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3 years ago

A magnetic compass is placed near an insulated copper wire. When the wire is connected to a battery and a current is created, th

Luba_88 [7]

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Every current through a wire produced a magnetic field. And since the magnetic field of Earth is weak, it will get attracted towards the wire.

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3 years ago

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The amount of energy necessary to remove an electron from an atom is a quantity called the ionization energy, Ei. This energy ca

Verizon [17]

Answer:

The value is $E_i = 1.5596 *10^{-18} \ J$

Explanation:

From the question we are told that

The wavelength is $\lambda = 48.2 nm = 48.2 *10^{- 9 }\ m$

The velocity is $v = 2.371*10^6 \ m/s$

The mass of electron is $m_e = 9.109*10^{-31} \ kg$

Generally the energy of the incident light is mathematically represented as

$E = \frac{h * c}{\lambda}$

Here c is the speed of light with value $c = 3.0 *10^{8} \ m/s$

h is the Planck constant with value $h = 6.62607015 * 10^{-34 } J\cdot s$

$E = \frac{6.62607015 * 10^{-34 }* 3.0 *10^{8}}{48.2 *10^{- 9 }}$

=> $E = 4.12 *10^{-18} \ J$

Generally the kinetic energy is mathematically represented as

$E_k = \frac{1}{2} * m_e * v^2$

=> $E_k = \frac{1}{2} * 9.109*10^{-31} * (2.371*10^6 )^2$

=> $E_k = 2.56 *0^{-18} \ J$

Generally the ionization energy is mathematically represented as

$E_i = 4.12 *10^{-18} - 2.56 *0^{-18}$

=> $E_i = 1.5596 *10^{-18} \ J$

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3 years ago

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Anvisha [2.4K]

Answer:

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Explanation:

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We know, work done is equal to potential energy plus kinetic energy. Since there is no change in any of these, the required work done would not change.

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