I think the correct answer from the choices listed above is the third option. The magnetic quantum number of an electron (m) designates the orientation in space of the orbital (electron cloud). <span>This number divides the subshell into individual orbitals which hold the electrons; there are 2l+1 orbitals in each subshell. </span>
<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg.
The key here is the conservation of momentum.
For the first truck, the momentum is
0(5100 + 4300)
The second truck has a starting momentum of
60(5100 + x)
And finally, after the collision, the momentum of the whole system is
42(5100 + 4300 + 5100 + x)
So let's set the equations for before and after the collision equal to each other.
0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x)
And solve for x, first by adding the constant terms
0(5100 + 4300) + 60(5100 + x) = 42(14500 + x)
Getting rid of the zero term
60(5100 + x) = 42(14500 + x)
Distribute the 60 and the 42.
60*5100 + 60x = 42*14500 + 42x
306000 + 60x = 609000 + 42x
Subtract 42x from both sides
306000 + 18x = 609000
Subtract 306000 from both sides
18x = 303000
And divide both sides by 18
x = 16833.33
So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums.
60(5100 + 16833.33) = 60(21933.33) = 1316000
42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000
They match. The 2nd truck was definitely over loaded.</span>
A<span>. speed= distance/ time
s= 4</span><span>.6m/s
d=60m
4</span><span>.6= 60/t
</span>4.6t= 60
t= 13.04 seconds
b. acceleration= (the change in velocity/speed)/(time) this is the same as a=Δv/t<span>
a= unkown
</span>Δv= (final speed - initial speed) = 3.1m/s - 4.6m/s= -1.5m/s
t=3 seconds
a=Δv/t= -1.5/3= -0.5m/s²
answer: the soccer player decelerated by 0.5m/s². This means his speed is decreasing by 0.5m/s². We know it is decreasing because the answer is negative.
c. list given information:
final velocity/speed(FS)= 0m/s
initial velocity/speed(IS)= 4m/s
distance(d)= 2m
time(t)= UNKOWN
acceleration(a)= UNKOWN
(side note: velocity and speed are almost the same thing. The difference between the two words is that velocity usually has a direction and can be negative. Speed cannot be negative. If your problems use the word "speed" I would recommend you continue to use the word "speed" as well. I wanted to clarify this so that you didn't think I was saying to divide velocity by speed.)
Equation: (final speed²)= (inital speed²)+ 2(distance)(acceleration)
FS²=IS²+2da
(0²)= (4²)+ 2(2)a
0=16+4a
-4a=16
a= -4m/s²
answer: The deceleration(decreasing acceleration) is 4m/s². This is because the speed was changing at a rate of negative 4 meters per second squared until reaching a final speed of 0m/s.
d. List given information:
Initial speed: 0m/s (we know he started from "rest" which means his IS was 0)
Final speed: UNKNOWN
time= 1.5seconds
distance= UNKOWN
acceleration= 3.1m/s²
Equation: distance= (initial speed * t) + ((1/2)*(acceleration)*(time²)
d= (IS)t + (1/2)at²
d= (0)(1.5)+ (1/2)(3.1)(1.5²)
d= 0 + 3.4785
d≈3.5 meters
Any confusion or questions? Hope this helped!
The conclusion that is best supported by the data is;
D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.