1/2 - 1/4x ≥ -1/4
Combine 1/4x to get x/4:
1/2 - x/4 ≥ -1/4
Subtract 1/2 from both sides:
-x/4 ≥ -1/4 - 1/2
Simplify:
-x/4 ≥ -3/4
Multiply both sides by 4:
-x ≥ -3/4 * 4
-x ≥ -3
Multiply each side by -1 ( and since you are multiplying by -1, you also need to reverse the inequality sign)
Answer: x ≤ 3
Simplify the following:
((8 x^3 y^2 a^2 b^4)/4)^(-2)
8/4 = (4×2)/4 = 2:
(2 x^3 y^2 a^2 b^4)^(-2)
Multiply each exponent in 2 x^3 y^2 a^2 b^4 by -2:
(x^(-2×3) y^(-2×2) a^(-2×2) b^(-2×4))/(2^2)
-2×3 = -6:
(x^(-6) y^(-2×2) a^(-2×2) b^(-2×4))/2^2
-2×2 = -4:
(y^(-4) a^(-2×2) b^(-2×4))/(2^2 x^6)
-2×2 = -4:
(a^(-4) b^(-2×4))/(2^2 x^6 y^4)
-2×4 = -8:
b^(-8)/(2^2 x^6 y^4 a^4)
2^2 = 4:
Answer: 1/(4 x^6 y^4 a^4 b^8) thus the answer is A
Answer:
y=-2x+17
Step-by-step explanation:
Your absolute value cannot be negative.
Just think of it as normal subtraction. They both have the same denominators all you need to do is subtract. 11/12-7/12 is 4/12 if you simplify which just means to find the number that both 4 and 12 can go into equally the simplified answer would be 1/3. You just need to divide 4 by both the top and the bottom (numerator and denominator).
