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Degger [83]
4 years ago
5

A cup of hot coffee can be cooled by placing a cold spoon in it. A spoon of which of the following materials would be most effec

tive for this purpose: aluminum, copper, iron, or glass? Assume all spoons have the same mass.
Physics
1 answer:
arsen [322]4 years ago
8 0

Answer: copper

Explanation: when a spoon is placed in a hot coffee, the coffee will cool off based on the concept of heat transfer.

The coffee is at a higher temperature compared to the spoon, hence there is conduction of heat by the spoon from the coffee.

Heat is now transfered from the coffee to the spoon, the rate of heat transfer ( for this case coffee to spoon) is dependent on some properties but for this case, the thermal conductivity is of the most important.

A material of high thermal conductivity have a very fast rate of heat transfer and a material of low thermal conductivity have a slow rate of heat transfer.

Below is the value of thermal conductivity for copper, aluminum, iron and glass.

Copper (385 w/m.K)

Aluminum (205 W/m.K)

Iron (79.5 W/m.K)

Glass (0.8 W/m.K)

It can been seen that copper has the highest value for thermal conductivity which implies that it will conduct heat faster compared to others thus cooling the coffee faster.

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show answer Incorrect Answer 33% Part (b) Find the radius of curvature, in meters, of the path of a proton accelerated through t
timofeeve [1]

The question is incomplete. Here is the complete question.

Consider an experimental setup where charged particles (electrons or protons) are first accelerated by an electric field and then injected into a region of constant magnetic field with a field strength of 0.65T.

part (a): What is the potential difference, in volts, required in the first part of the experiment to accelerate electrons to a speed of 6.2 x 10⁷m/s?

part (b): Find the radius of curvature, in meters, of the path of a proton accelerated trhough this same potential after the proton crosses into the region with the magnetic field.

part (c) what is the ratio of the radii of curvature for a proton and an electron traveling through this apparatus?

Answer: (a) V = - 109.44 x 10² V

              (b) r_{p}= 9.95 x 10⁻¹ m

              (c) ratio = 1800

Explanation: (a) <u>Potential</u> <u>difference</u> is defined as the energy a charged particle has between two points in a circuit. It is calculated as

\Delta V=\frac{pe}{q}

where

pe is potential energy

q is charge

and its unit is joule/coulomb of Volts (V).

To determine potential difference required to accelerate a particle, we have to use the principle that the total energy of a system is conserved and one transforms into the other.

In this case, potential energy is transformed in kinetic energy:

pe = V.q

ke = \frac{1}{2}m.v^{2}

so

V.q=\frac{1}{2} m.v^{2}

V=\frac{m.v^{2}}{2q}

Calculating:

V=\frac{9.11.10^{-31}(6.2.10^{7})^{2}}{2(-1.6.10^{-19})}

V = -109.44 x 10²V

Potential difference of an electron to have speed of 6.2x10⁷m/s is -109.44 x 10²V.

(b) A particle has a circular motion when there is a magnetic force acting on it.

Velocity and magnetic force are always perpendicular to each other. Because of that, there is no work on the particle and so, kinetic energy and speed are constant. Since magnetic force supplies centripetal force:

F_{mag} = F_{c}

qvB=\frac{mv^{2}}{r}

r=\frac{mv}{qB}

The radius of the curvature, for a proton, will be:

r=\frac{1.67.10^{-27}.6.2.10^{7}}{1.6.10^{-19}.0.65}

r = 9.95 x 10⁻¹m

The raius of curvature, when it is a proton, is 0.995m.

(c) Radius of curvature, if it was a electron:

r=\frac{9.11.10^{-31}.6.2.10^{7}}{1.6.10^{-19}.0.65}

r = 54.33 x 10⁻⁵m

ratio = \frac{9.95.10^{-1}}{54.33.10^{-5}}

ratio = 1800

Ratio of radii of curvature is 1800, meaning curvature created when it is a proton is 1800 times bigger than when it is a electron.

5 0
4 years ago
How to calculate the velocity? the answer is 5.4 m/s I need the explication
Vanyuwa [196]

Answer: sq. root of .735

Explanation:

multiply two on both sides.

(2) *2,94 = (0,200 * v^2) (2)

588 = 0400 * 2v^2

divide by 400 on both sides

1.47 = 2v^2

divide by 2 on both sides

.735 = v^2

take square root of both sides

\sqrt{.735)  or .85732141

7 0
3 years ago
Which of the following values can you find by calculating the slope of a graph of velocity versus time? A. Acceleration B. Veloc
Lady_Fox [76]
A. acceleration.

On a Velocity vs Time graph the slope will always be equal to the acceleration. I.e. if the slope is negative, so is the acceleration and vice versa.
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zalisa [80]
No I do not agree. It is because work is done when force acting o a body displace or covers certain displacement in the direction of force applied .
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3 years ago
When light passes from a faster medium into a slower medium, which of the following explains what will occur?
beks73 [17]

When light passes from a faster medium into a slower medium, light will be refracted toward a line drawn perpendicular to the point of refraction. <em>(B)</em>

5 0
4 years ago
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