Question

Toluene, c6h5ch3, is a liquid compound similar to benzene, c6h6. it is the starting material for other substances, including trinitrotoluene (tnt). find the molality of toluene in a solution that contains 35.6 g of toluene and 125 g of benzene.

Answer 1

Toulene = 35.6 g 
Benzene = 125 g = 0.125 kg
 Molecular weight of Toluene C6H5CH3 = 92.1g/mol
 Moles of toulene = 35.6 g / 92.1 g/mol = 0.3865 mol

 Now the molarity of the toulene in the given solution = 0.3865 / 0.125 = 3.092 m 
 Molarity of C6H5CH3 = 3.092 m

Answer 2

Answer:

3.08 m

Explanation:

To calculate the molarity, you have to use the following formula:  

$\frac{moles of solute}{kg of solvent}$

From the question, we already have the mass of the solvent (benzene); However, for the calculation of molality, we require the solvent in Kg, therefore we do the conversion from g to kg:  

125 g of benzene = 0.125 kg of benzene.  

To obtain the number of moles of solute we have to use the molecular weight of toluene, which is 92.14  

To convert from g to moles, we divide the grams of toluene by the molecular weight:  

$\frac{35.6g}{92.14gmol^{-1} }$

Therefore, we have 0.386 moles of toluene.  

The last step will be to replace all the values in the molality formula:  

$\frac{0.386 moles of toluene}{0.125 kg of benzene}$ = 3.08 m

I hope this clarifies your inquiry.