Answer:
Explanation:
Given:
- moment of inertia of the skater with extended arms,
- moment of inertia of the the skater with pulled-in arms,
- angular velocity of the skater with extended arms,
<u>Using the law of conservation of angular momentum:</u>
a₀). You know ...
-- the object is dropped from 5 meters
above the pavement;
-- it falls for 0.83 second.
a₁). Without being told, you assume ...
-- there is no air anyplace where the marshmallow travels,
so it free-falls, with no air resistance;
-- the event is happening on Earth,
where the acceleration of gravity is 9.81 m/s² .
b). You need to find how much LESS than 5 meters
the marshmallow falls in 0.83 second.
c). You can use whatever equations you like.
I'm going to use the equation for the distance an object falls in
' T ' seconds, in a place where the acceleration of gravity is ' G '.
d). To see how this all goes together for the solution, keep reading:
The distance that an object falls in ' T ' seconds
when it's dropped from rest is
(1/2 G) x (T²) .
On Earth, ' G ' is roughly 9.81 m/s², so in 0.83 seconds,
such an object would fall
(9.81 / 2) x (0.83)² = 3.38 meters .
It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was
(5.00 - 3.38) = 1.62 meters
above the pavement. That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.
Answer:
The answer is 80 Joules
Explanation:
Electrical energy = Q x V
Energy = 2 x 40
= 80
I just took the test and it was right :D
The correct answer is B.
I hope this helped! :D
To determine, the final velocity we use one kinematic equation. It would be 2ax = vf^2 - v0^2. The initial velocity would be zero since it starts from rest. Therefore, the equation would be:
vf = √(2ax) where a is the acceleration ( a = g ) and x is the height
vf = √(2)(9.8)(25)
vf = - 22.14 m/s
