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3 years ago

Which is the force of repulsion between two positively-charged particles?

2 answers:

4 0

answer>>>>electric force <<<<by the way i don't like physics but i answer this for you ^-^

This is because centripetal force is just the net force of a circular motion. There are no attractive or repulsive forces here. This is not the case here. 
The gravitational force is a force reliant on mass and attraction of the masses. There are attractive forces here, but not really repulsive forces. 
The electric force is the only one that would make sense because it has to do with a relationship between charges and includes both repulsive and attractive forces.

Alla [95]3 years ago

4 0

electric force is your answer

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Anvisha [2.4K]

Answer:

North pole

Explanation:

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Unlike poles attract while like poles repel

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Since the North pole is the opposite of the south pole, the North pole will be at the pointed end of the nail so that it can attract the steel magnet.

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1 year ago

If no work is done, the total energy is not changed. In that situation, if the kinetic energy changes, what must happen to the p

Norma-Jean [14]

Answer:

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Explanation:

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3 years ago

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Mice21 [21]

Answer:

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3 years ago

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3 years ago

Read 2 more answers

During what time interval was the object traveling most quickly?

anygoal [31]

ANSWER

0s to 3s

EXPLANATION

To find the time interval where the object was traveling more quickly, we have to find the velocity of the object during each interval.

From a position-time graph, we can obtain the velocity of the object from the slope of the graph in each interval. To find those slopes, we just have to divide the vertical difference by the time interval.

The interval from 0s to 3s:

$v=\frac{7-3}{0-3}=-\frac{4}{3}m/s$

The interval from 3s to 5s and the interval from 7s to 8s have a horizontal line, so the slope is zero and therefore the velocity is zero - meaning that the object was not moving during these periods.

The interval from 5s to 7s,

$v=\frac{5-3}{7-5}=\frac{2}{2}=1m/s$

And the interval from 8s to 12s,

$v=\frac{0-5}{12-8}=-\frac{5}{4}m/s$

Two of these three velocities are negative. Negative velocity indicates that the object is moving backward.

From these velocities, the greatest one, in absolute value, is the one between 0s to 3s. During this interval, the object is moving backward but at the greatest velocity.

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1 year ago