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3 years ago

Compare the wavelength and frequency of a radio wave to the wavelength and frequency of a gamma ray?

Chemistry

1 answer:

IgorC [24]3 years ago

6 0

Answer:

Wavelength of Radio wave = 10² meter = 100 meters, frequency 10 power 6 htz,

Wavelength of gamma ray = 10 power -12 meters = 0.000000000002 meters, frequency 10 power 20 htz

frequenc

Explanation:

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andreev551 [17]

The average atomic mass of the imaginary element : 47.255 amu

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% ..

isotope E-47 47.011 amu, 87.34%

isotope E-48 48.008 amu, 6.895

isotope E-49 50.009 amu, 5.77%

The average atomic mass :

$\tt avg~mass=0.8734\times 47.011+0.06895\times 48.008+0.0577\times 50.009\\\\avg~mass=41.059+3.310+2.886\\\\avg~mass=47.255~amu$

5 0

3 years ago

List three different forms of potential energy

Wewaii [24]

Answer:

Types of Potential Energy

Elastic Potential Energy. Anything that can act like a spring or a rubber band can have elastic potential energy. ...

Gravitational Potential Energy. There is a constant attractive force between the Earth and everything surrounding it, due to gravity. ...

Chemical Potential Energy.

(IF THIS HELPED CAN YOU GIVE ME A BRAINYLEST PLEASE?)

3 0

3 years ago

A car's fuel efficiency is 39.0 miles per gallon. What is its fuel efficiency in kilometers per liter? (1.6094 km=1 mile)(1 gall

MrRa [10]

Answer:

the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

Explanation:

The computation of the full efficiency in kilometers per liter is shown below:

39.0 miles ÷ gallon = (39.0 miles ÷ gallon) × (1.6094 km ÷ 1 miles) × (1 gallon ÷ 3.79 L)

Now cut the opposite miles and gallons

So, the fuel efficiency would be

= 16.561 kilometers per liter

Hence, the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

5 0

3 years ago

a- If an Lithium (atomic number 3) atom has a -2 charge, how many electrons does it have? b- Why do you do it this way? c- Is th

Darina [25.2K]

Answer:

Explanation:

A lithium atom with an atomic number of 3 and a charge of -2 will have a total number of electrons.

The atomic number is the number of protons in an atom. For a neutral atom that has not gained or lost electrons, the atomic number is the same as the number of electrons.

neutral atom: atomic number of electrons

For neutral atom of lithium, we will have 3 electrons

Now, lithium with a charge of -2 has gained two more electrons to the original 3 this now makes it 5.

ii.

It is an anion because it is negatively charged.

Negatively charged particles are called anion.

6 0

2 years ago

Match each transition metal ion with its condensed ground-state electron configuration. A [Ar]3d2 B [Ar]4s23d3 C [Kr]4d10 D [Xe]

madreJ [45]

Answer:

$Mn^{2+}$ : - F . $[Ar]3d^{5}$

$Hg^{2+}$ : - G. $[Xe]4f^{14}5d^{10}$

$La^{3+}$ : - D. $[Xe]$

$Fe^{3+}$ : - F. $[Ar]3d^{5}$

$Ag^{+}$ : - C. $[Kr]4d^{10}$

$Co^{3+}$ : - E. $[Ar]3d^{6}$

Explanation:

The electronic configuration of the element Mn is:-

$[Ar]3d^{5}4s^2$

For, $Mn^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Hg is:-

$[Xe]4f^{14}5d^{10}6s^2$

For, $Hg^{2+}$ , 2 electrons are lost, thus the configuration is:-

$[Xe]4f^{14}5d^{10}$

The electronic configuration of the element La is:-

$[Xe]5d^{1}6s^2$

For, $La^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Xe]$

The electronic configuration of the element Fe is:-

$[Ar]3d^{6}4s^2$

For, $Fe^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{5}$

The electronic configuration of the element Ag is:-

$[Kr]4d^{10}5s^1$

For, $Ag^{+}$ , 1 electron is lost, thus the configuration is:-

$[Kr]4d^{10}$

The electronic configuration of the element Co is:-

$[Ar]3d^{7}4s^2$

For, $Co^{3+}$ , 3 electrons are lost, thus the configuration is:-

$[Ar]3d^{6}$

7 0

3 years ago