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devlian [24]
3 years ago
8

£ 5.1.4 Quiz: Hydrocarbons What is the name of this molecule?

Chemistry
2 answers:
Lisa [10]3 years ago
5 0
£ is pounds sterling not a molecule
lisov135 [29]3 years ago
3 0
£ is not a molecule. It is a currency. That is pounds sterling, used in the U.K.
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What are the freezing and boiling points of water on the celsius temperature table
KengaRu [80]
There are 100 degrees between the freezing (0°) and boiling points (100°) of water on the Celsius scale and 180 degrees between the similar points (32° and 212°) on the Fahrenheit scale.


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2 years ago
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How many grams are in 1.70 moles of Ca(NO3)2?
Andru [333]

The number of grams in 1.70 moles of Ca(NO₃)₂ is 384.2 grams

<h3>How to determine the mass of Ca(NO₃)₂</h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

With the above formula, we can determine the mass of Ca(NO₃)₂ as illustrated below:

  • Mole of Ca(NO₃)₂ = 1.70 moles
  • Molar mass of Ca(NO₃)₂ = 40 + 3[14 + (16 × 3)] = 40 + 3[14 + 48] = 40 + 3(62) = 40 + 186 = 226 g/mol
  • Mass of Ca(NO₃)₂ = ?

Mole = mass / molar mass

1.70 = Mass of Ca(NO₃)₂ / 226

Cross multiply

Mass of Ca(NO₃)₂ = 1.70 × 226

Mass of Ca(NO₃)₂ = 384.2 grams

Thus, the mass of 1.70 moles of Ca(NO₃)₂ is 384.2 grams

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4 0
1 year ago
Why is it important to control all of the variables except one in an experiment?
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Any given experiment has numerous control variables, and it's important for a scientist to try to hold all variables constant except for the independent variable. If a control variable changes during an experiment, it may invalidate the correlation between the dependent and independent variables.



It’s copied and pasted from google so make sure to put it in your words :)

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Answer:

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6 0
3 years ago
1.42 g H2 is allowed to react with 10.4 g N2 , producing 2.14 g NH3 . Part A What is the theoretical yield in grams for this rea
Bad White [126]

Taking into account the reaction stoichiometry, the theorical yield for the reaction is 8.0467 grams of NH₃.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

3 H₂ + N₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • H₂: 3 moles
  • N₂: 1 mole
  • NH₃: 2 moles

The molar mass of the compounds is:

  • H₂: 2 g/mole
  • N₂: 28 g/mole
  • NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • H₂: 3 moles ×2 g/mole= 6 grams
  • N₂: 1 mole ×28 g/mole= 28 grams
  • NH₃: 2 moles ×17 g/mole= 34 grams

<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 28 grams of N₂ reacts with 6 grams of H₂, 10.4 grams of N₂ reacts with how much mass of H₂?

mass of H_{2} =\frac{10.4 grams of N_{2}x 6 grams of H_{2} }{28 grams of N_{2}}

<u><em>mass of H₂= 2.2286 grams</em></u>

But 2.2286 grams of H₂ are not available, 1.42 grams are available. Since you have less mass than you need to react with 10.4 grams of N₂, H₂ will be the limiting reagent.

<h3>Definition of theorical yield</h3>

The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

<h3>Theoretical yield in this case</h3>

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 34 grams of NH₃, 1.42 grams of H₂ form how much mass of NH₃?

mass of NH_{3} =\frac{1.42 grams of H_{2} x 34 grams of NH_{3}}{6grams of H_{2} }

<u><em>mass of NH₃= 8.0467 grams</em></u>

Then, the theorical yield for the reaction is 8.0467 grams of NH₃.

Learn more about the reaction stoichiometry:

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7 0
1 year ago
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