D is the answer
in V-t graph, tan α= velocity/time=acceleration
The kinetic energy of the mass at the instant it passes back through its equilibrium position is about 1.20 J
<h3>Further explanation</h3>
Let's recall Elastic Potential Energy formula as follows:
where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
Let us now tackle the problem!
<u>Given:</u>
mass of object = m = 1.25 kg
initial extension = x = 0.0275 m
final extension = x' = 0.0735 - 0.0275 = 0.0460 m
<u>Asked:</u>
kinetic energy = Ek = ?
<u>Solution:</u>
<em>Firstly , we will calculate the spring constant by using </em><em>Hooke's Law</em><em> as follows:</em>
<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity
The answer is that it is constant. The relation between electric field and electric potential is given as, E= -gradient (V). The E, the partial rate of change of Electric potential, in the equation implies that the V, the partial differential of the potential of the three-dimensional space (assuming it is considered) is constant.
Answer:
makinig ka kasi sa titser mo tas intindihin mo bobo
Answer:
Explanation:
according to third equation of motion
2as=vf²-vi²
vf²=2as+vi²
vf=√2as+vi²
vf=√2as+vi
vf=√2*2*4+3
vf=√16+3
vf=4+3=7
so final velocity is 7 m/s