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3 years ago

I am in need of some serious help here, I skipped this last time so I got a bad grade

Mathematics

1 answer:

lesantik [10]3 years ago

8 0

1. ab= 6 x 3 = 18 1) = 18

2. c + 4 = 2 + 4 = 6 2) = 6

3. a/b = 6/3 = 2 3) = 2

4. a - b - 6 - 3 = 3 4) = 3

5. 2c = 2(2) = 4 5) = 4

6. b/3 = 3/3 = 1 6) = 1

7. a - 1 = 6 - 1 = 5 7) = 5

8. 6 + c= 6 + 2 = 8 8) = 8

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mr. tyler has a total of $5,000 in savings account and in a mutual fund. If he has x dollars in the savings account, how much do

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5000-x is the number of dollars in the mutual fund

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3 years ago

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Solve 10(1 + 3b) = −20, justifying each step with an algebraic property.

Delicious77 [7]

The correct answer is B = -1

10(1 + 3B) = -20

10 + 30B = -20

-20 - 10 = -30

30B = -30

B = -1

Hope this helps :)

4 0

3 years ago

Plz help ASAP! I will mark brainliest if correct

MaRussiya [10]

A = L^2
A = L^2 = 2^2 + 4^2 (Pythagorean’s theorem)
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3 years ago

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Vitek1552 [10]

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4 years ago

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Suppose that in a senior college class of 500500 students, it is found that 179179 smoke, 228228 drink alcoholic beverages, 1

olga2289 [7]

Answer: a) 0.16, b) 0.058, and c) 0.856.

Step-by-step explanation:

Since we have given that

Number of students = 500

Number of students smoke = 179

Number of students drink alcohol = 228

Number of students eat between meals = 119

Number of students eat between meals and drink alcohol = 59

Number of students eat between meals and smoke = 72

Number of students engage in all three = 30

a) Probability that the student smokes but does not drink alcohol is given by

$P(S-A)=P(S)-P(S\cap A)\\\\P(S-A)=\dfrac{179}{500}-\dfrac{99}{500}\\\\P(S-A)=\dfrac{179-99}{500}\\\\P(S-A)=\dfrac{80}{500}\\\\P(S-A)=0.16$

b) eats between meals and drink alcohol but does not smoke.

$P((M\cap A)-S)=P(M\cap A)-P(M\cap S\cap A)\\\\P((M\cap A)-S)=\dfrac{59}{500}-\dfrac{30}{500}\\\\P((M\cap A)-S)=\dfrac{59-30}{500}\\\\P((M\cap A)-S)=\dfrac{29}{500}\\\\P((M\cap A)-S)=0.058$

c) neither smokes nor eats between meals.

$P(S'\cap M')=1-P(S\cup M)\\\\P(S'\cap M')=1-\dfrac{72}{500}\\\\P(S'\cap M')=\dfrac{500-72}{500}\\\\P(S'\cap M')=\dfrac{428}{500}=0.856$

Hence, a) 0.16, b) 0.058, and c) 0.856.

5 0

3 years ago