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Vikki [24]
3 years ago
8

I am in need of some serious help here, I skipped this last time so I got a bad grade

Mathematics
1 answer:
lesantik [10]3 years ago
8 0
1. ab= 6 x 3 = 18             1) = 18

2. c + 4 = 2 + 4 = 6           2) = 6

3. a/b = 6/3 = 2                 3) = 2

4. a - b - 6 - 3 = 3             4) = 3

5. 2c = 2(2) = 4                5) = 4

6. b/3 = 3/3 = 1                6) = 1

7. a - 1 = 6 - 1 = 5           7) = 5

8. 6 + c= 6 + 2 = 8          8) = 8
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Ginger wants to join a gym. She goes to the local gym and is told that there is a one-time fee of $100 to join and then a monthl
Mnenie [13.5K]
D. 30m + 100 because there is a monthly fee of 30 a month so that show that 30 is always reappearing and 100 is just the one time fee
5 0
2 years ago
Find the upper 20%of the weight?
meriva

Answer:

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Upper 20% of weights:

The upper 20% of the weighs are weighs of at least X, which is found when Z has a p-value of 0.8. So X when Z = 0.84. Then

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - \mu}{\sigma}

X = 0.84\sigma + \mu

The upper 20% of the weighs are weights of at least X, which is X = 0.84\sigma + \mu, in which \sigma is the standard deviation of all weights and \mu is the mean.

6 0
2 years ago
un carro que se mueve con velocidad constante recorre 120 km en 75 minutos,¿en que tiempo recorrera el carro una distancia de 20
Ivan

Answer:

320 minutos

Step-by-step explanation:

4 0
3 years ago
Which statement justifies why
Marina CMI [18]
You have to give more information
7 0
3 years ago
Which expression has the same value as the one below?<br> 38 + (-18)
Fittoniya [83]

Answer:

D

Step-by-step explanation:

38+(-18) can be changed to 38-18 and the answer will still be the same

8 0
3 years ago
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