Answer:
Europa
Explanation:
it is though that to have a subsurface liquid of water
C- more than one light year or B-exactly one light year
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2
Answer:
Try looking for some kind of answer that has to do with .61904
Explanation:
52 g x 1 mol/ (molar mass of aluminum fluoride) 84 g = .619047619
Sorry if this is wrong but that's my best guess
Answer:
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Explanation:us8s f7 ds8a das8 jf7sd 87sd 45s67f8
