Question

An experiment is conducted using nitrogen monoxide and bromine reacted to form nitrosyl bromide. Calculate Keq for the reaction using the following equation data. [NOBr] = 0.0474 mol/L [NO] = 0.312 mol/L [Br2] = 0.259 mol/L Keq =

Answer 1

The answer is Keq= .0891

Answer 2

Answer:

0.0891

Explanation:

Keq is the equilibrium constant.

Keq= products/ reactants

Let’s take a chemical reaction:

aA -> bB

Keq = $\frac{[B]^b}{[A]^a}$

Equilibrium constant is the ratio of the molar concentration of the products to the molar concentration of the reactants. The coefficients are raised to the power of the respective molar concentrations.  

The balanced reaction is:

2NO + Br₂ → 2NOBr

Keq = $\frac{[NOBr]^2}{[NO] [Br2]}$ = $\frac{(0.0474)^2}{(0.312)^2(0.259)}$ 

       = 0.0891