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ANEK [815]
3 years ago
5

Hana fills a cup with sandy ocean water. She pours the mixture through a filter. What does she collect that passes through the f

ilter?

Chemistry
2 answers:
Alisiya [41]3 years ago
6 0
The solution of salt and water
miss Akunina [59]3 years ago
3 0

Answer: Hana collects the ocean water that passes through the filter.

Explanation;

When the Hana fills allows the sandy ocean mixture through a filter she will observe that, the sand particles present in the mixture getting collected on the filter and the water seeping down through the pores of the filter. This process followed by Hana is known as filtration process (as shown in figure attached).

In the end, Hana will be able collect the ocean water without sand present in it.


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If you can smell your grandmother’s perfume from across the room, you are experiencing the result of which liquid property?
cestrela7 [59]
The appropriate answer is D. volatility. Volatility refers to the susceptibility of liquids to vaporize. Perfume is liquid when applied but because of volatility, it has a tendency to vaporize and so it will convert to a gas and diffuse across the room. The process by which a liquid changes to a vapor is called evaporation. 
5 0
3 years ago
Dimitri Mendeleev organized an early version of the Periodic Table in order of increasing __________.
omeli [17]

c) Atomic Mass.

Hope it is helpfull


6 0
3 years ago
What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K
vlada-n [284]

Answer:

=1.666 liters

Explanation:

1 mole of a has at standard temperature and pressure occupies a volume of 22.4 liters.

0.5 moles of nitrogen occupy a volume of (0.5 moles×22.4 dm³/mol)/ 1

=11.2 liters.

Standard pressure= 1 atmosphere (Atm)

Standard temperature = 273.15 Kelvin

According to Combined gas equation, P₁V₁/T₁=P₂V₂/T₂

Let us take the conditions under standard conditions as the reference, with the subscript 1 and the conditions under the 5L container to be scenario 2 with subscript 2.

Therefore P₂ =P₁V₁T₂/T₁V₂

Substituting for the values we get:

P₂= (1 atm× 11.2L ×203K)/ (273K×5L)

=1.666 atm

5 0
3 years ago
A manganese electrode was oxidized electrically. If the mass of the electrode decreased by 225 mg during the passage of 1580 cou
qwelly [4]

Answer:

<u>Oxidation state of Mn = +4</u>

Explanation:

Atomic mass of Mn = 55g/mol

From Faraday's law of electrolysis,

Electrochemical equivalent = \frac{mass}{charge}

i.e Z = \frac{m}{Q} = \frac{0.225g}{1580C} = 0.0001424 g/C

But Equivalent weight, E = atomic mass ÷ valency  = Z × 96,485

⇒ \frac{55}{valency} = 0.0001424 × 96,485

<u>∴ Valency of Mn = +4</u>

8 0
3 years ago
Please help i will give extra points
GREYUIT [131]

Answer:

B. Coal

Explanation: Coal is mined to produce energy.

3 0
2 years ago
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