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Anna007 [38]
3 years ago
5

Whick ions profuce similar colors in the flame tests?

Chemistry
1 answer:
arlik [135]3 years ago
5 0

Ba2+ and Cu2+, and Sr2+ and Li+

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A student dissolved 3.50g of copper (II) nitrate in water and mixed it with a solution of sodium carbonate. The student recovere
Arisa [49]

Answer: If the theoretical yield is 2.35g then the percent yield is 80.4%

Explanation:

Given: Actual yield = 1.89 g

Theoretical yield = 2.35 g

Formula used to calculate the percentage yield is as follows.

Percent yield = \frac{actual yield}{theoretical yield} \times 100

Substitute the values into above formula as follows.

Percent yield = \frac{actual yield}{theoretical yield} \times 100\\= \frac{1.89}{2.35} \times 100\\= 80.4 percent

Thus, we can conclude that if the theoretical yield is 2.35g then the percent yield is 80.4%

3 0
3 years ago
Give examples of simple machines advantage and disadvantage
ra1l [238]
Simple machines help reduce the amount of work being done, as they help by using a simple function. One disadvantage is that they do not help completely. 
6 0
3 years ago
Which statement about organic matter is false? A. Organic matter comes from organisms. B. Organic matter contains the element, c
siniylev [52]

B. Organic matter contains the element, carbon.


3 0
3 years ago
Read 2 more answers
The table describes how some substances were formed.
lisabon 2012 [21]

Explanation:

Which is a pure substance?

1. soda

2. gasoline

3. salt water

4. carbon dioxide

carbon dioxide

Bromine, a liquid at room temperature, has a boiling point of 58°C and a melting point of -7.2°C. Bromine can be classified as a

1. compound.

2. impure substance.

3. mixture.

4. pure substance.

pure substance.

6 0
3 years ago
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What is the net ionic equation for 2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 6NaOH
tatuchka [14]

Answer:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

Explanation:

First of all, let us balance the equation to give;

2Sb(OH)3 (s) + 3Na2S (aq) = Sb2S3 + 3NaOH

Now, we can observe the presence of positive Sodium ions (Na+) and negative hydroxyl ions (OH-) on both left and right sides of the equation.

Now, the two ions will cancel out. These ions are not really involved in the overall reaction and thus do not require being written in the overall equation. Hence, the overall net ionic reaction can now be written as:

2Sb^(+3) (aq) + 3S^(-2) (aq) = Sb_2•S_3

6 0
3 years ago
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