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enot [183]
3 years ago
9

How many moles are in 4.3 x 1022 molecules of H 3 PO 4 ?

Chemistry
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

0.071 mole

Explanation:

As discovered from Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules.

This simply means that 1 mole of H3PO4 also contains 6.02x10^23 molecules.

If 1 mole H3PO4 contains 6.02x10^23 molecules,

Then, xmol of H3PO4 will contain 4.3x10^22 molecules i.e

Xmol of H3PO4 = 4.3x10^22/6.02x10^23 = 0.071 mole

From the calculations made above, 4.3x10^22 molecules of H3PO4 have 0.071 mole of H3PO4

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Consider the generic reaction: 2 A(g) + B(g) → 2 C(g). If a flask initially contains 1.0 atm of A and 1.0 atm of B, what is the
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Answer:

b. 1.5 atm.

Explanation:

Hello!

In this case, since the undergoing chemical reaction suggests that two moles of A react with one moles of B to produce two moles of C, for the final pressure we can write:

P=P_A+P_B+P_C

Now, if we introduce the stoichiometry, and the change in the pressure x we can write:

P=1.0-2x+1.0-x+2x

Nevertheless, since the reaction goes to completion, all A is consumed and there is a leftover of B, and that consumed A is:

x=\frac{1.0atm}{2}=0.5atm

Thus, the final pressure is:

P=1.0-2(0.5)+1.0-(0.5)+2(0.5)\\\\P=1.5atm

Therefore the answer is b. 1.5 atm.

Best regards!

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Calculate the pH of a 0.10 M HCN solution that is 0.0070% ionized.
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Answer:

D) 5.15

Explanation:

Step 1: Write the equation for the dissociation of HCN

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

Step 2: Calculate [H⁺] at equilibrium

The percent of ionization (α%) is equal to the concentration of one ion at the equilibrium divided by the initial concentration of the acid times 100%.

α% = [H⁺]eq / [HCN]₀ × 100%

[H⁺]eq = α%/100% × [HCN]₀

[H⁺]eq = 0.0070%/100% × 0.10 M

[H⁺]eq = 7.0 × 10⁻⁶ M

Step 3: Calculate the pH

pH = -log [H⁺] = -log 7.0 × 10⁻⁶ = 5.15

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