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enot [183]
3 years ago
9

How many moles are in 4.3 x 1022 molecules of H 3 PO 4 ?

Chemistry
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

0.071 mole

Explanation:

As discovered from Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules.

This simply means that 1 mole of H3PO4 also contains 6.02x10^23 molecules.

If 1 mole H3PO4 contains 6.02x10^23 molecules,

Then, xmol of H3PO4 will contain 4.3x10^22 molecules i.e

Xmol of H3PO4 = 4.3x10^22/6.02x10^23 = 0.071 mole

From the calculations made above, 4.3x10^22 molecules of H3PO4 have 0.071 mole of H3PO4

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Which elements have the quantum numbers (4,3,-2,+1/2) and (5,2,-1,-1/2)
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The elements are samarium (Sm) and silver (Ag).  

<em>Quantum numbers (4,3,-2,+½)  </em>

<em>n</em> = 4: Principal quantum number = 4.  

<em>l</em> = 3: Element has 4f electrons  

It is <em>conventional</em> to list quantum numbers in decreasing order.  

<em>Hund’s rule </em>states that all the orbitals must be half-filled with electrons having the same spin before any can receive a second electron.  

We get the following table:  

<u>Element </u><em><u>n</u></em><u> </u><em><u>l</u></em><u>   </u><em><u>m</u></em><u>ₗ </u><em><u>m</u></em><u>ₛ</u>  

    La      4 3   3 +½  

    Ce     4 3   2 +½  

    Pr      4 3   1  +½  

    Nd    4 3   0 +½  

    Pm   4 3  -1   +½  

    Sm   4 3 -2 +½  

The element is samarium, Sm.  

<em>Quantum numbers (5,2,-1,-½)  </em>

<em>n</em> = 5: Principal quantum number = 5.  

<em>l</em> = 2: Element has <em>5d</em> electrons  

We get the following table:  

<u>Element </u><em><u>n</u></em><u>  </u><em><u>l m</u></em><u>ₗ mₛ</u><em><u>  </u></em>

<em>  </em>   Y       5<em> </em>2  2 +½  

    Zr      5 2  1 +½  

    Nb    5 2  0 +½  

    Mo   5 2  -1 +½  

    Tc    5 2  -2 +½  

    Ru   5 2   2  -½  

    Rh   5 2   1   -½  

    Pd   5 2   0  -½  

    Ag   5 2  -1  -½  

The element is silver, Ag.

<em>Note</em>: These assignments assume that there are <em>no exceptions</em> in the Periodic Table.

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