Answer: The work done to lift the 2 N rock was 6 Joules.
Explanation:
Weight of the Rock = 2 Newtons
So, the force required to lift this rock will be equal to its weight or greater than its weight
Minimum force required to lift the Rock = 2 N
Displacement of the Rock when force was applied = 3 m,
Work Done: It is defined as product of force applied to the object into displacement of the object.
The work done to lift the 2 N rock was 6 Joules.
Answer : The diatomic molecule of chlorine, Cl₂, is held together by a SINGLE covalent bond.
Covalent Bond :
It is type of chemical bond, which is formed by sharing of electron between atoms . The covalent bond is formed between two non metals . The valance electron are shared to form the bond . The shared electrons are known as BONDING electron pair and the electron pair which do not take part in bonding are known as NON- BONDING electron pair. Example : O₂ , H₂ , H₂O, NH₃ etc .
Formation of covalent bond in Cl₂ :
Chlorine is present in group 17 in p block , It is a non metal .
The electronic configuration of Cl is : 1s² 2s² 2p⁶ 3s² 3p⁵ .
Since the outer shell is n= 3 , which has 7 electrons in it , hence Cl has 7 valence electrons in it .
From electronic configuration , it can be seen that Cl need 1 electron to complete its octet (3s² 3p⁶ ). Hence when two Cl atoms come close they share one-one electron with each other (as shown in image ) .
Now the octet of both the atom are complete and they are in stable state together .
When both Cl atom share one e⁻ , there is a bond formed between Cl atoms . One bond consists of 2⁻ . Hence in Cl₂ SINGLE covalent bond present .
Cl + Cl -> Cl₂
Answer: D) 1 lone pair, square pyramidal
Explanation:
Formula used :
where,
V = number of valence electrons present in central atom = 7
N = number of monovalent atoms bonded to central atom = 5
C = charge of cation = 0
A = charge of anion = 0
Now we have to determine the hybridization of the molecule.
Bond pair electrons = 5
Lone pair electrons = 6-5 = 1
The number of electrons are 6 that means the hybridization will be and the electronic geometry of the molecule will be octahedral .
But as there are five atoms around the central iodine atom, the sixth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be square pyramidal.