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yaroslaw [1]
4 years ago
8

Sodium (chemical symbol Na) is atomic number 11 and is in the first column of the periodic table so it has one valence electron.

What is the typical charge when sodium forms a charged particle (ion)
A) +1

B) +2

C) -1

D) -2
Chemistry
2 answers:
lisabon 2012 [21]4 years ago
7 0
Na is cation so it loses electron to be positive and become stable losing one valence shells one electron so it's oxidation number is +1 ie A is correct
denpristay [2]4 years ago
5 0

Answer:

A +1

Explanation:

A +1

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The solid dissolves quickly is a chemical or physical reaction
Vladimir79 [104]

Answer:

i think it is chemical wait no physical

Explanation:

4 0
3 years ago
Which of the pairs below would be the best choice for a pH 5 buffer? HF/NaF, K a (HF) = 3.5 × 10-4 HC2H3O2/KC2H3O2, K a (HC2H3O2
kati45 [8]

Answer:

HC₂H₃O₂/KC₂H₃O₂

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the basic buffer solution as:


pH=pK_b+log\frac{[salt]}{[acid]}


For a best pair, the pKa value must be equal to pH.

NH₃/NH₄Cl forms a basic buffer and cannot account for pH = 5

out of the acidic buffer given,

So, HF , Ka = 3.5 × 10⁻⁴ , So pKa = 3.46

HC₂H₃O₂ , Ka = 1.8 × 10⁻⁵ , So pKa = 4.77

<u>The best pair to show pH = 5 is HC₂H₃O₂/KC₂H₃O₂</u>

3 0
3 years ago
The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh
Vinil7 [7]

Answer:

Here's what I get  

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}

3. Check:

Compare the final concentration with the original

\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}

7 0
3 years ago
Given the following reactions and subsequent ∆H values, what is the ∆H for the reaction below? 4CO2(g) + 2H2O(g) 2C2H2(g) + 5O2(
melisa1 [442]
The problem ask on which of the following reactions and subsequent values and the value is given on you question. Base on your data and also to my formulation, solution and further simplification about the problem and the given values, i came up with an answer of <span>∆Hrxn = 5∆Hf(O2(g)) + 2∆Hf(C2H2(g)) - 2∆Hf(H2O(g)) - 4∆Hf(CO2(g)).</span>
7 0
3 years ago
If you use a horizontal force of 32.0 N to slide a 12.5 kg wooden crate across a floor at a constant velocity, what is the coeff
sergejj [24]

Answer:

Value of coefficient of kinetic friction is 0.26 .

Explanation:

Given:

Mass of wooden crate, m = 12.5 kg.

Horizontal force to keep the block moving with constant velocity, F = 32.0 N.

Since, the block is moving with constant velocity.

So, net force experience by it is zero.

Therefore, fore of friction is equal to applied force.

Now, force of friction , F=\mu_kN  (  here \mu_k is coefficient of kinetic friction and N is normal force)

Therefore, \mu_kN=\mu_k\times mg=\mu_k\times 12.5 \times 9.8=122.5\times \mu_k

Now, both forces are equal.

122.5\times \mu_k=32\\\mu_k=\dfrac{32}{122.5}=0.26      

The value of coefficient of kinetic friction is 0.26 .

Hence, it is the required solution.

6 0
4 years ago
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