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beks73 [17]
3 years ago
14

What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84? C14H42O84

Chemistry
2 answers:
Arada [10]3 years ago
8 0

The answer is CH₃O₆


An empirical formula is the simplest ratio. So, let's simplify the ratio

14 : 42 : 84

All numbers are divisible by 14, therefore:

14 : 42 : 84 = (14/14) : (42/14) : (84:14) = 1 : 3 : 6

So, it contains 1 C-atom, 3 H-atoms, and 6 O-atoms



kati45 [8]3 years ago
6 0
C:H:O = 14:42:84 = 7:21:42 = 1:3:6

CH₃O₆
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Explanation:

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0.076 J/gºC.

Explanation:

From the question given above, the following data were obtained:

Mass (M) of object = 1.32 kg

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Next, we shall convert 1.32 kg to grams (g). This can be obtained as follow:

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Therefore,

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Next, we shall convert –1.95 kJ to joule (J). This can be obtained as follow:

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Therefore,

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Finally, we shall determine the specific heat capacity of the object. This can be obtained as follow:

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Heat (Q) released = –1950 J

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Specific heat capacity (C) =?

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–1950 = 1320 × C × –19.5

–1950 = –25740 × C

Divide both side by –25740

C = –1950 / –25740

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Thus, the specific heat capacity of the object is 0.076 J/gºC.

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