1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lidiya [134]
3 years ago
8

Consider a system to be one train car moving toward another train car at rest. When the trains collide, the two cars stick toget

her. What is the total momentum of the system after the collision?
Before Collison
Car 1 Car 2
m1 =600kg m2 =400kg
v1 =4 m/s v2 =0 m/s
Choices:
800kg × m/s
1,600kg × m/s
2,400kg × m/s
4,000kg × m/s
Someone please help! The lady who tought me did a terrible job of explaining how to do this!
Physics
2 answers:
pickupchik [31]3 years ago
8 0

As per the question, the system consists of two cars.

The the masses of two cars are denoted as-  m_{1} \ and\ m_{2} \ respectively

The two cars undergoes collision with each other. Here collision must be inelastic in nature.

Let the velocities of each car is denoted as-  v_{1} \ and\ v_{2} \ respectively

It is given that masses of two cars and initial velocities-

m_{1} =600 kg          v_{1} =4m/s

m_{2} = 400kg         v_{2} =0 m/s

 

First we have to calculate the total momentum of the system before collision.

The momentum of a body is the product of its mass with velocity.

Momentum of car 1:

                           p_{1} =m_{1} v_{1}

                                  =600kg*4m/s

                                  =2400\ kg\ m\ s^-1

The momentum of car 2:

                             p_{2} =m_{2} v_{2}

                                   =400\ kg*0\ m/s

                                   =\ 0\ kg\ m\ s^-1

Now the total momentum of the system is :

                        p_{1} +p_{2}

                             =[2400+0]\ kg\ m\ s^-1

                             =2400\ kg\ m\ s^-1

Now we are asked to calculate the total momentum of the system after collision.

The basic condition in case of any type of collision is that it is in accordance with law of conservation of linear momentum.

Hence, the momentum will be conserved here.

It means  the total momentum before collision must be equal to the total momentum after collision.

Hence, the correct answer to the question will be 2400 kg m/s.



                 

3241004551 [841]3 years ago
6 0

Answer : 2400 kgm/s.

Explanation :

It is given that,

Mass of train 1, m_1=600\ kg

Mass of train 2, m_2=400\ kg

<em>When the trains collide, the two cars stick together. So, it is a perfectly inelastic collision. The momentum of the system will remain conserved.</em>

Momentum of train car 1, p_1=m_1v_1=2400\ Kgm/s

Momentum of train car 2, p_2=m_2v_2=0

So, total momentum of the system after the collision will be same as before the collision.

p_f=p_1+p_2

p_f=2400\ kgm/s

Hence, after the collision total momentum of the system would be 2400 kgm/s.

You might be interested in
A river flows due east at 1.60 m/s. A boat crosses the river from the south shore to the north shore by maintaining a constant v
Citrus2011 [14]

Answer:

part (a) v\ =\ 10.42\ at\ 81.17^o towards north east direction.

part (b) s = 46.60 m

Explanation:

Given,

  • velocity of the river due to east = v_r\ =\ 1.60\ m/s.
  • velocity of the boat due to the north = v_b\ =\ 10.3\ m/s.

part (a)

River is flowing due to east and the boat is moving in the north, therefore both the velocities are perpendicular to each other and,

Hence the resultant velocity i,e, the velocity of the boat relative to the shore is in the North east direction. velocities are the vector quantities, Hence the resultant velocity is the vector addition of these two velocities and the angle between both the velocities are 90^o

Let 'v' be the velocity of the boat relative to the shore.

\therefore v\ =\ \sqrt{v_r^2\ +\ v_b^2}\\\Rightarrow v\ =\ \sqrt{1.60^2\ +\ 10.3^2}\\\Rightarrow v\ =\ 10.42\ m/s.

Let \theta be the angle of the velocity of the boat relative to the shore with the horizontal axis.

Direction of the velocity of the boat relative to the shore.\therefore Tan\theta\ =\ \dfrac{v_b}{v_r}\\\Rightarrow Tan\theta\ =\ \dfrac{10.3}{1.60}\\\Rightarrow \theta\ =\ Tan^{-1}\left (\dfrac{10.3}{1.60}\ \right )\\\Rightarrow \theta\ =\ 81.17^o

part (b)

  • Width of the shore = w = 300m

total distance traveled in the north direction by the boat is equal to the product of the velocity of the boat in north direction and total time taken

Let 't' be the total time taken by the boat to cross the width of the river.\therefore w\ =\ v_bt\\\Rightarrow t\ =\ \dfrac{w}{v_b}\\\Rightarrow t\ =\ \dfrac{300}{10.3}\\\Rightarrow t\ =\ 29.12 s

Therefore the total distance traveled in the direction of downstream by the boat is equal to the product of the total time taken and the velocity of the river\therefore s\ =\ u_rt\\\Rightarrow s\ =\ 1.60\times 29.12\\\Rightarrow s\ =\ 46.60\ m

7 0
3 years ago
Please help me fill out the chart.??
LekaFEV [45]

Answer:unbalanced: have direction,Change an objects motion, causes object to accelerate

Balanced:Do not change an objects motion, Net forces equal sum of all forces on object, and Does not equal 0 N

Explanation: Thats all I know Hoped I helped sum

5 0
3 years ago
5. What is the amount of force required to accelerate a 20 kg object at a rate of 5 m/sz?
GenaCL600 [577]

Force required is 100 N

<u>Given that;</u>

Rate of acceleration = 5 m/s²

Mass of object = 20kg

<u>Find:</u>

Force required

<u>Computation:</u>

Force = Mass × Acceleration

Force required = Rate of acceleration × Mass of object

Force required = 20 × 5

Force required = 100 N

Learn more:

brainly.com/question/17506203?referrer=searchResults

3 0
2 years ago
How does a fuse work?
Vilka [71]

Answer:

A. a material burns out when current is excessive

5 0
2 years ago
What is the definition of Cubit
disa [49]

Answer:

See below.

Explanation:

Cubit is a unit of length based on the length of the forearm from the elbow to the tip of the middle finger and usually equal to about 18 inches (46 centimeters).

It is an ancient unit of length used in ancient Egypt and is also known as "ancient Egyptian royal cubit."

Other similar units of measurements are displayed in the image below. Thanks!

7 0
2 years ago
Other questions:
  • For the meter stick shown in figure 10-4, the force F1 10.0 N acts at 10.0 cm. What is the magnitude of torque due to F1 about a
    13·1 answer
  • A physicist is calibrating a spectrometer that uses a diffraction grating to separate light in order of increasing wavelength (λ
    6·1 answer
  • Some one please help me!!!!!!!
    8·1 answer
  • Are bases chemically the same as acids true or false
    15·1 answer
  • When a unbalanced force act on an object , the object moves with what motion?
    6·1 answer
  • Unlike the news media, which may be biased, science reporting can be depended on to be objective and not influenced by governmen
    10·1 answer
  • Describe the pattern you see in the chart PLEASE HURRY IS URGENT
    6·1 answer
  • What formula can I use to solve speed and temperature in soundwave​
    8·1 answer
  • In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by
    6·1 answer
  • Find the resultant force of the following forces :
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!