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snow_lady [41]
3 years ago
14

In the frog genus, when certain species attempt to mate with other species, embryo development is halted at various stages inclu

ding zygotic segmentation, blastula formation, gastrulation, or in the final phases of embryo development. The stage at which the developing frog arrests depends on the species involved in the cross. This is an example of
a.

hybrid breakdown.

b.

hybrid sterility.

c.

hybrid inviability.

d.

sexual isolation.
Biology
1 answer:
Katarina [22]3 years ago
4 0

Answer: Option D.

Sexual isolation.

Explanation:

Sexual isolation is a process in which a species of organism is unable to breed or mate from related species successfully due to environment, physiological, behavioral or genetic difference making its to depend on species involved in the cross. Examples is found in amphibians frogs and toads. Breakdown of sexual isolation lead to hybrid sterility, hybrid invaibility or poor gene flow.

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Child 2 is polydactylous, otherwise normal; Child 4 has cystic fibrosis and is polydactylous.What is the genotype of the mother?
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Answer:

PpCc; ccpp; ccPp; 1/2

Explanation: The complete correct question is as follows

A polydactylous woman, otherwise normal, marries a healthy normal man. Their four children have the following phenotypes:

Child 1 is normal in all respects; Child 3 has cystic fibrosis, otherwise normal Child 2 is polydactylous, otherwise normal; Child 4 has cystic fibrosis and is polydactylous. A. What is the genotype of the mother? B. What is the genotype of child 3? C. What is the genotype of child 4? D. What is the chance that child 1 is heterozygous for cystic fibrosis?

We represent the traits of the parents with the following

P= Polydactyly

p=normal

C= normal

c= abnormal (cystic fibrosis

A. What is the genotype of the mother

Mother PpCc (polydactylous)

Father: ppCc (healthy normal)

B. What is the genotype of child 3?

Applying the mendel's cross link between the mother's genotype and father's genotype,

PpCc × ppCc

Child 3 will be ccpp (abnormal with cystic fibrosis)

C. What is the genotype of child 4?

Applying the mendel's cross link between the mother's genotype and father's genotype,

PpCc × ppCc

Child 4 will be ccPp

D. What is the chance that child 1 is heterozygous for cystic fibrosis?

Applying the mendel's cross link between the mother's genotype and father's genotype,

PpCc × ppCc

Child will be Cccc

The chance is 1/2

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