Answer: amount = 2466.95L
Explanation:
given that the speed is = 1900./kmh i.e. 1hr/900km
distance = 1050km
the fuel burns at a rate of 74.4 L/min
therefore the amount of fuel that the jet consumes on a 1050.km becomes;
total fuel used = time × fuel burning rate
where time = distance / speed
∴ total fuel used (consumed) = time × fuel burning rate
total fuel consumed = (1050km × 1hr/1900km) × (60min/ 1hr × 74.4L/1min)
total fuel consumed = 2466.95L
Answer:
Explanation:
1. the 1/2 reaction that occurs at the cathode
3Cl2(g) +6e^- -------------> 6Cl^- (aq)
2 the 1/2 reaction that occurs at the anode
2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-
2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-
E0 = -0.59v
3Cl2(g) +6e^- -------------> 6Cl^- (aq)
E0 = 1.39v
3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)---------> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)
E0cell = 0.80v
-<u><em>Oxygen</em></u>
According to Google these are the percentages of the <em>Earths Atmosphere</em>
<em>1</em> 78% - Nitrogen
<u>2</u> 21% - Oxygen
<em>3</em> 0.9% - Argon
<em>4 </em>0.3 - Carbon Dioxide with very small percentage of other elements.
