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Oxana [17]
3 years ago
5

Compare and contrast rutherford's "planetary model" of the atom with our current understanding of an atom's internal structure.

Physics
1 answer:
andrew11 [14]3 years ago
5 0
<span>Rutherford felt that the atom had an internal structure much like our solar system, with a nucleus surrounded by orbiting electrons. Today, we know that the electrons inhabit specific shells and sub-shells, and there is an order to which these electrons are located.</span>
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A manufacturer claims its cleanser works twice as fast as any other. Could test be performed to support the claim? Explain
lora16 [44]

Yes, a test could be performed to support the claim.

 

Hypothesis: The claim that a manufacturer’s cleanser works twice as fast as any other cleanser.

 

So, based from this hypothesis, we can perform the following tests:

We assign Cleanser A to the manufacturer that claims that their cleanser works twice as fast as any other cleanser and Cleanser B to the cleanser to be compared with.

 

1.       Get two tiles and put the same amount of stain on them.

2.       Apply Cleanser A on the first tile and Cleanser B on the second tile.

3.       Apply the same amount of force in removing the stains on both tiles

4.       Record the amount of time it takes to remove the stains on each tile.

4 0
3 years ago
Elements with atomic numbers 58 through 71 are part of what series?
maria [59]

Elements with atomic numbers from 58 through 71 are part of the

<span>lanthanide</span> series <span />

3 0
3 years ago
Read 2 more answers
Which layer of the earth can be seen from the open hole
umka21 [38]

Answer:

the inner core

Explanation:

6 0
3 years ago
Read 2 more answers
Tell whether each element has a high or low electronegativity : bromine, chlorine, potassium, lithium
finlep [7]

Answer:

Bromine-2.8 high

Chlorine-3.0 high

Potassium-0.8 low

Lithium-1.0 low

Explanation:

3 0
3 years ago
*PHYSICS HELP*
sveta [45]
My calculator is about 1cm thick, 7cm wide, and 13cm long.

Its volume is (length) (width) (thick) = (13 x 7 x 1) = 91 cm³ .

The question wants me to assume that the density of my calculator
is about  the same as the density of water.  That doesn't seem right
to me.  I could check it easily.  All I have to do is put my calculator
into water, watch to see if sinks or floats, and how enthusiastically. 
I won't do that.  I'll accept the assumption.

If its density is actually 1 g/cm³, then its mass is about 91 grams.

The choices of answers confused me at first, until I realized that
the choices are actually 1g, 10² g, 10⁴ g, and 10⁶ g.

My result of 91 grams is about 100 grams ... about 10² grams.

Your results could be different.
3 0
3 years ago
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