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lana [24]
3 years ago
8

At high speeds, a particular automobile is capable of an acceleration of about 0.540 m/s^2. At this rate, how long (in seconds)

does it take to accelerate from 91.0 km/hr to 104 km/hr?
Physics
1 answer:
Mama L [17]3 years ago
5 0

Answer:

t = 6.68 seconds

Explanation:

The acceleration of the automobile, a=0.54\ m/s^2

Initial speed of the automobile, u = 91 km/hr = 25.27 m/s

Final speed of the automobile, v = 104 km/hr = 28.88 m/s

Let t is the time taken to accelerate from u to v. It can be calculated as the following formula as :

t=\dfrac{v-u}{a}

t=\dfrac{28.88-25.27}{0.54}

t = 6.68 seconds

So, the time taken by the automobile to accelerate from u to v is 6.68 seconds. Hence, this is the required solution.

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Answer:

Neutrons

Explanation:

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Which of the following statement(s) is
alexgriva [62]

Answer:

Explanation:

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Dafna1 [17]

Answer:

30 degrees

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See atached diagram

4 0
2 years ago
suppose that you look into a photometer's eyepiece and the fluorescent disks appear to be equal in intensity. If the distance be
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Use the Inverse square law, Intensity (I)<span> of a light </span>is inversely proportional to the square of the distance(d).

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3 0
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what law of motion that states that an object will remain at rest or move in a straight line at a constant speed unless it is ac
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