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3 years ago

X²+64=0 ayudaaaaaaaaaaaaaaaaaaa

Mathematics

1 answer:

Elan Coil [88]3 years ago

8 0

Answer:

I'm confused

Step-by-step explanation:

maybe you should help me....

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove

gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

$v = \frac{d}{t}$

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time $t_1$ , distance of $d_1$ , v = 40. So

$v = \frac{d}{t}$

$40 = \frac{d_1}{t_1}$

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is $v = 60$ .

On the first day, he drove 2 more hours, which means that for the second day, the time is: $t_1 - 2$

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: $d_1 - 20$

Thus

$v = \frac{d}{t}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

System of equations:

Now, from the two equations, a system of equations can be built. So

$40 = \frac{d_1}{t_1}$

$60 = \frac{d_1 - 20}{t_1 - 2}$

Find the total distance traveled in the two days:

We solve the system of equation for $d_1$ , which gets the distance on the first day. The distance on the second day is $d_2 = d_1 - 20$ , and the total distance is:

$T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20$

From the first equation:

$d_1 = 40t_1$

$t_1 = \frac{d_1}{40}$

Replacing in the second equation:

$60 = \frac{d_1 - 20}{t_1 - 2}$

$d_1 - 20 = 60t_1 - 120$

$d_1 - 20 = 60\frac{d_1}{40} - 120$

$d_1 = \frac{3d_1}{2} - 100$

$d_1 - \frac{3d_1}{2} = -100$

$-\frac{d_1}{2} = -100$

$\frac{d_1}{2} = 100$

$d_1 = 200$

Thus, the total distance is:

$T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380$

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0

2 years ago

What is another form for 1.12

avanturin [10]

1 and 3 over 25

Be sure to rate me up and give me a thanks :D

6 0

2 years ago

Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3

gayaneshka [121]

Answer:

E is not a subspace of $\mathbb{R}^2$

Step-by-step explanation:

E is not a subspace of $\mathbb{R}^2$

In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0

2 years ago

Find the mean of thw data 11,11,12,13,13,13,14,14,15,15,16,16,18

amid [387]

Answer:

the mean is 13

Step-by-step explanation:

The way to find the mean of a set of numbers is to add all the numbers together and divide the sum by the number of numbers. so 11 + 11 + 12 + 13+ 13 + 13 + 14 + 14 + 15 + 15 + 16 + 16 + 18 / 13 = 13.9

4 0

3 years ago

5. If Amber decides to mail copies of her photos to the 45 residents of her grandmother’s assisted living facility, the new func

pav-90 [236]

Answer: please find the answer in the explanation

Step-by-step explanation:

From the information given from the question, the initial function representing her photo sharing is:

F(x) = 3(4)^2

F(x) = 3 × 16 = 48 photos

Then the new graph has an upward shift ( translation) of 45 units

The new function representing her photo sharing is:

F(x) = 3(4)^2 + 45

F(x) = 48 + 45

F(x) = 93 photos.

8 0

3 years ago

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