Answer:
Explanation:
According to Equations of Projectile motion :

vsin(x) = 11 * 9.8 / 2 = 53.9 m/sec
(A) v (Initial velocity) = 11 * 9.8 / 2 * sin(35) = 94.56 m/sec

(B) Maximum Height = 53.9 * 53.9 / 2 * 9.8 = 142.2 m

(C) Horizontal Range = 94.56 * 0.81 * 11 = 842.52 m
The maximum diffraction order seen is 3.
<h3>What is the maximum diffraction order seen?</h3>
We know that the maximum angle of diffraction Q_m of the furthest bright fringe < Q = 90 degrees.
Here we need to compute the nth bright fringe for which is approximated to 90 degrees.
The angle of nth bright fringe is given by;
sin(Q_m) = n(λ)N
Approximating Q_m ≈ 90 degrees.
sin (90) = nλN
n = sin (90) / (λN)
n = 1 / ((580 x 10⁻⁶)500)
n = 3.5 orders
Since, we knew that Q_m < 90 degrees, we will choose n = 3 as the maximum number of orders.
Thus, the maximum diffraction order seen is 3.
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Answer:
2.24 m/s²
Explanation:
Using equation of motion
s = ut +
at²
u = 0 , t = 3.17 s , s = 11.26 m
Put these values in the equation above
11.26 = 0 +.5 x a( 3.17)²
a = 2.24 ms⁻².
So acceleration due to gravity on that planet will be 2.24 m s⁻².
Answer:
Mass and velocity.
Explanation:
Kinetic energy <u>is the energy that an object has due to its movement</u>, mathematically it is represented as follows:

where
is the mass of the object, and
is its velocity at a given point in time.
So we can see that to find the kinetic energy just before the ball hits the gound, we need the quantities:
- mass of the ball
- velocity of the ball before it hits the ground
With the knowledge of these two quantities the kinetic energy of the ball before touching the gound can be determined.
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