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defon
3 years ago
5

6.0 x 10^4 x 3.1 x 10 ^-1

Mathematics
1 answer:
GarryVolchara [31]3 years ago
5 0
=18600 
Hope this helped!
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Answer:

The rock hits the ground between <u>2</u> seconds and <u>2.5</u> seconds after it is dropped

Step-by-step explanation:

The given table is presented as follows;

\begin{array}{ccl}t&h(t)&Description\\0&20&Initial \ height\\0.5&18.8&Rock \ in \ downward \ motion\\1&15.1&\\1.5&9&\\2&0.4&The \ height \ just \ before \ the \ rock \ hits \ the \ ground \\2.5&-10.6&The \ calculated \ height \ after\ the \ rock \ hits \ the \ ground \\3&-24.1&Calculated \ height \ after\ the \ rock \ hits \ the \ ground\end{array}

Therefore, the rock hits the ground between t = 2 seconds and t = 2.5 seconds after it is dropped.

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