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3 years ago

Which of the following is the correct name for the compound HF?

Chemistry

2 answers:

alexira [117]3 years ago

6 0

Name for the compound HF is Hydrogen fluoride.
Hope this helps!

natali 33 [55]3 years ago

3 0

Answer : The correct name of the compound $HF$ is hydrogen fluoride.

Explanation :

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

The nomenclature of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written then, and a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on..

$HF$ is a covalent compound because sharing of electrons takes place between hydrogen and fluorine. Both the elements are non-metals and hence, will form covalent bond.

So, the name of the compound $HF$ is hydrogen fluoride.

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What is the function of a lyase enzyme?

elena55 [62]

Answer:

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2 years ago

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3 years ago

A student used 1.2 g of hydrate in the first trial and 1.6 g in the second trial. Explain fully why her mass percent of water wi

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Both trials of 1.2 g and 1.6 g will have the same mass percent of water because the ratio of the salt to the water of hydration is always constant for any hydrated salt.

<h3>Water of hydration</h3>

For every hydrated salt, the ratio of the salt to the water of hydration remains constant irrespective of the amount of salt taken for experimental analysis.

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1 year ago

Consider the titration of 82.0 mL of 0.140 M Ba(OH)2 by 0.560 M HCl. Calculate the pH of the resulting solution after the follow

oksano4ka [1.4K]

Answer:

a) pH = 13.447

b) pH = 13.176

Explanation:

Ba (OH)₂ is a strong base and ionizes completely in solution to give barium amend hydroxide ions.

The equation of the dissociation of Ba(OH)₂ is given below:

Ba(OH)₂ ----> Ba2+ + 2OH-

1 mole of Ba(OH)₂ produces 2 Moles of OH- ions

a) Before the addition of HCl, i.e.,when 0.00 mL of HCl has been added;

Concentration of hydroxide ions, [OH-] = 0.140 x 2 = 0.a) [OH-] = 0.100 x 2 = 0.280

pOH = -log [OH-]

pOH = -log (0.280)

pOH = 0.553

pH = 14 - 0.553= 13.447

b) pH when 15.0 mL HCl has been added

Moles Ba(OH)₂ = concentration × volume

Volume of Ba(OH)₂ = 82.0 mL = 0.082 L, concentration = 0.140 M

moles of Ba(OH)₂ = 0.082 x 0.140 = 0.01148 moles

moles OH- produced by 0.01148 moles of Ba(OH)₂ = 2 x 0.01148= 0.02296

moles HCl = 0.0150 L x 0.560 = 0.0084

moles of H+ produced by 0.0084 HCl = 0.0084

0.0084 H+ willnreact with 0.0084 moles of OH-

moles OH- left after the reaction = 0.02296 - 0.0084 = 0.01456 moles

total volume of new solution = (82 +15) mL = 97 mL => 0.097 L

Concentration of OH- ions = moles / volume

[OH-] = 0.01456 / 0.097 = 0.1501

pOH = -log [OH-]

pOH = -log (0.150)

pOH = 0.824

pH = 14 - 0.824

pH = 13.176

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2 years ago