Answer: first option, the work output of the hairdryer will be less than the work input.
Explanation:
1) The work output measured in watts is the power of hair dryer measured in joules per second.
2) The hair dryer converts electrical energy from the wall outlet to mechanical and thermal energy: hot wind.
3) Nevertheless, you can never expect a 100% efficiency of the machines: due to friction, some energy is converted into useless energy.
So, efiiviency = power output / power input< 1 ⇒
power output = work output / time
input power = work input / time
⇒ work output / work input < 1
⇒ work output < work input.
Which is the first option: the work output of the hairdryer will be less than the work input
Assuming that the number of mols are constant for both conditions:
Now you plug in the given values. V_1 is the unknown.
Separate V_1
V= 162.782608696 L
There are 2 sig figs
V= 160 L
Hello!
So, we are given a ball with a density of 1100 kg/m³, and two liquids: water (1000 kg/m³) and honey (1400 kg/m³). Our goal is to determine if the ball will sink or float in the given liquids.
Let's take two common substances: water and ice. Water has a density of 1000 kg/m³ and ice has a density of about 917 kg/m³. You would notice that the ice is always floating when you put ice and water together. This would occur if you have other substances.
Here's what you should know:
- If the density of an object is greater than the liquid it is in, then that object will sink.
- If the density of an object is less than the liquid it is in, then that object will float.
Since the ball has a density of 1100 kg/m³, and water's density is 1000 kg/m³, then the ball will sink. If the ball is placed in honey, then it will float because the density of honey (1400 kg/m³) is greater than the ball's density.
Therefore, objects with a greater density than the surrounding liquid sink, while objects with a smaller density than the surrounding liquid float, which is the fourth choice.
Photosynethesis, respiration, and combustion.
