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lisabon 2012 [21]
3 years ago
6

Hi, Which of these percentages is closest in value to 7/9

Mathematics
1 answer:
Gnoma [55]3 years ago
4 0
To find a percentage, you need to divide 7 by 9 to find out what 7/9 is.
It turns out to be 0.777 repeating. 
To find a percentage, you need to move the decimal place over by two to the right, so 7/9 is equals to 77.77%.
If you round that, then 77.77% is closest to 78%.


Hope this helps!
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A random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph. From past information, it is kn
loris [4]

Answer:

95 percent confidence interval for μ is determined by

(60.688 ,  69.312)

a) be the same

Step-by-step explanation:

<u>Step (i)</u>:-

Given data a random sample of 121 automobiles traveling on an interstate showed an average speed of 65 mph.

The sample size is n= 121

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

<u>Step (ii) :</u>-

Given  The 95 percent confidence interval for μ is determined as

(61.08, 68.92)

we are to reduce the sample size to 100 (other factors remain unchanged) so

given The sample size is n= 100

The mean of the sample x⁻ = 65mph.

The standard deviation of the population is 22 mph

σ = 22mph

<u>Step (iii)</u>:-

95 percent confidence interval for μ is determined by

(x^{-} - 1.96\frac{S.D}{\sqrt{n} } , x^{-} + 1.96 \frac{S.D}{\sqrt{n} } )

(65 - 1.96\frac{22}{\sqrt{100} } , 65 + 1.96 \frac{22}{\sqrt{100} } )

(65 - 4.312 ,65 +4.312)

(60.688 ,  69.312) ≅(61 ,69)

This is similar to (61.08, 68.92) ≅(61 ,69)

<u>Conclusion</u>:-

it become same as (61.08, 68.92)

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