Please help

2 answers:

7 0

#1 : C. $Mg(CN)2$

#2: B. $N205$

#3: D. $Ti(CIO4)3$

#4: A. But you maked a little mistake. It's $Ni(NO3)2$

#5: D. Cobalt (III) Acetate.

#6: B.

#7: C.

# 8: A.

# 9: C.

# 10: A.

# 11: C.

# 12: B.

Pachacha [2.7K]3 years ago

5 0

1. C : Mg(CN)2
2. B : N2O5
3. D : Ti(ClO4)3
4. A : Ni(NO3)3
5. D : Cobalt (III) Acetate
6. B : Nickel(II) sulfate
7. C : Dinitrogen Tetrafluoride
8. A : Phosphorus pentachloride<em />
9. C : Metallic <em>(<!> This is the only one I'm not 100% sure of)</em>
10. A : Ionic
11. C : Metallic
12. B : Covalent

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How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg

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Explanation :

First we have to calculate the mole of $PbCrO_4$ .

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Now we have to calculate the moles of $PbSO_4$ .

The balanced chemical reaction will be,

$PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4$ produced from 1 mole of $PbSO_4$