b the absence of a nucleus
Hahahaaaa none of the above but IF <span>(c) is
1/2 mole of NaCl and 1/3 mole of MgCl2 instead,
then C is the right ans :)</span>
A) NaCl = 58.44 g/mol
number of moles : 2.14 / 58.44 = 0.0366 moles
V = n / M => 0.0366 / 0.270 = 0.1355 L
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b) C2H6<span>O = 46.06 g/mol
</span>number of moles : 4.30 / 46.06 = 0.0933 moles
<span>V = n / M => 0.0933 / 1.50 = 0.0622 L
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c) CH3COOH = 60.0 g/mol
number of moles : 0.85 / 60.0= 0.0141 moles
V = n / M => <span> 0.0141 </span>/ 0.30 = 0.047 L
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hope this helps!