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Marysya12 [62]
3 years ago
15

According to the kinetic-molecular theory, the collision between two ideal gas particles is a result of

Chemistry
2 answers:
rosijanka [135]3 years ago
5 0

It is a result of neither attraction nor repulsion. They interact freely without any kinetic or chemical reaction.

Svetlanka [38]3 years ago
4 0
<span>The correct answer is neither attraction nor repulsion.</span>
<span>Kinetic Molecular Theory explains that gas particles are in constant motion and exhibit perfectly elastic collisions. The motion of gas particles is random, meaning that there are no attractive forces on each other or on their surroundings. When two particles collide, the total kinetic energy is conserved.</span>
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Why are numbers not used to designate the position of the functional group in propanone and butanedione?
Sholpan [36]
The reason for this is that <span>these two ketones are so small that they have only one possible ketone. So the number is usually omitted. Normally the ketone group needs a number but these two are exceptions</span>
6 0
3 years ago
A) co2 is non polar while h2o is polar why?
almond37 [142]

Answer:

A) Polar molecules have a non-zero net dipole moment. Both CO2 and H2O have two polar bonds. However the dipoles in the linear CO2 molecule cancel each other out, meaning that the CO2 molecule is non-polar. The polar bonds in the bent H2O molecule result in a net dipole moment, so H2O is polar.

B) In PCl5, in addition to equitorial bonds which lie in the same plane, there are axial it suffers more repulsion it is longer than the other bonds; hence PCl5 decomposes to form PCl3. So PCl5 is highly reactive. Source(s): 5 Heavy ElectroNegative atoms in One Molecule Lone Pair.

C) In h2o there is hydrogen bonding because oxygen has a high electronegativity (only second to flourine). so, the hydrogen atoms from other molecules of water forms a hydrogen bonds with oxygen resulting in intermolecular hydrogen bonding. therefore at room temperature h2o is a liquid and h2s is a gas.

Hope this helps also can you answer my question after since I helped you prepare for your exam.

Explanation:

7 0
3 years ago
Write the equilibrium-constant expression for the reactionA(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)in terms of [A], [
Ilia_Sergeevich [38]

Answer:

K_{c} = [\text{C}]^{2}[\text{[D]}

Explanation:

\rm A(s)+3B(l) \, \rightleftharpoons \, 2C(aq)+D(aq)

The general formula for an equilibrium constant expression is

K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}

Solids and liquids are not included in the equilibrium constant expression.

Thus, for this reaction,  

K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}

3 0
3 years ago
0.3 / 48 tsps x 100 =<br> help mee
Vinil7 [7]

Answer:

0.625

Explanation:

i hope this is correct! and that it helps!! c:

5 0
3 years ago
Which states of matter have particles that move independently of one another with very little attraction?
maks197457 [2]
Gas -- move very independently as compared to a liquid, for instance.

Plasma -- related to a gas although it has positively charged ions and negatively charged electrons.
8 0
3 years ago
Read 2 more answers
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