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sattari [20]
2 years ago
10

Calculate to three significant digits the density of chlorine pentafluoride gas at exactly and exactly . You can assume chlorine

pentafluoride gas behaves as an ideal gas under these conditions.
Chemistry
1 answer:
slega [8]2 years ago
7 0

Answer:

Density is 6.16g/L

Explanation:

<em>... at exactly -15°C and exactly 1atm...</em>

<em />

Using general gas law:

PV = nRT

We can find density (Ratio of mass and volume) in an ideal gas as follows:

P/RT = n/V

<em>To convert moles to grams we need to multiply the moles with Molar Weight, MW:</em>

n*MW = m

n = m/MW

P/RT = m/V*MW

P*MW/RT = m/V

<em>Where P is pressure: 1atm;</em>

<em>MW of chlorine pentafluoride: 130.445g/mol</em>

<em>R is gas constant: 0.082atmL/molK</em>

<em>And T is absolute temperature: -15°C+273.15 = 258.15K</em>

<em />

Replacing:

P*MW/RT = m/V

1atm*130.445g/mol / 0.082atmL/molK*258.15K = m/V

6.16g/L = m/V

<h3>Density of the gas is 6.16g/L</h3>

<em> </em>

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