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3 years ago

A magnetic field of 14 x 10^-3 T exists at the corner of a circular coil of radius 20cm having 15

Physics

1 answer:

musickatia [10]3 years ago

3 0

The current in the coil is 297 A

Explanation:

The magnetic field of a circular coil carrying a current is given by

$B=\frac{\mu_0 NI}{2R}$

where

$\mu_0 =4\pi \cdot 10^{-7} Tm/A$ is the vacuum permeability

N is the number of turns in the coil

I is the current in the coil

R is the radius of the coil

For the coil in this problem, we have:

$B=14\cdot 10^{-3} T$

R = 20 cm = 0.20 m

N = 15

Solving the equation for I, we find the current in the coil:

$I=\frac{2BR}{\mu_0 N}=\frac{2(14\cdot 10^{-3})(0.20)}{(4\pi \cdot 10^{-7})(15)}=297 A$

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What often happens to light when it travels from one medium to another

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Answer:

Although the speed changes and wavelength changes, the frequency of the light will be constant. The frequency, wavelength, and speed are related by: The change in speed that occurs when light passes from one medium to another is responsible for the bending of light, or refraction, that takes place at an interface.

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3 years ago

Reaction time is the lapse of time between muscular movement and external stimuli. True or false

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How much conventional current must you run in a solenoid with radius = 0.05 m and length = 0.39 m to produce a magnetic field in

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Answer:

Explanation:

radius of the solenoid, r = 0.05 m

length of the solenoid, l = 0.39 m

Magnetic field of the solenoid, B = 2 x 10^-5 T

Number of turns, N = 200

The magnetic field of the solenoid is given by

$B=\mu _{0}ni$

where, i be the current and n be the number of turns per unit length

n = N / l = 200 / 0.39 = 512.8

$2\times 10^{-5}=4 \times 3.14\times 10^{-7}\times 512.8\times i$

i = 0.031 A

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3 years ago

An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 ∘C and rejects he

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Answer:

2.36 x 10^6 J

Explanation:

Tc = 0°C = 273 K

TH = 22.5°C = 295.5 K

Qc = heat used to melt the ice

mass of ice, m = 85.7 Kg

Latent heat of fusion, L = 3.34 x 10^5 J/kg

Let Energy supplied is E which is equal to the work done

Qc = m x L = 85.7 x 3.34 x 10^5 = 286.24 x 10^5 J

Use the Carnot's equation

$\frac{Q_{H}}{Q_{c}}=\frac{T_{H}}{T_{c}}$

$Q_{H}=286.24\times 10^{5}\times \frac{295.5}{273}$

QH = 309.8 x 10^5 J

W = QH - Qc

W = (309.8 - 286.24) x 10^5

W = 23.56 x 10^5 J

W = 2.36 x 10^6 J

Thus, the energy supplied is 2.36 x 10^6 J.

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4 years ago

A laser is shone through a double slit and a particular interference pattern is observed on a screen some distance away. If the

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If the separation between the openings in a laser is increased, then the distance between the interference fringes decreases

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Interference fringe refers to bands caused by different lights which can be found in phase or not each other.

Distances between laser fringes are short which is due to light wavelength.
The interference fringes can be estimated by knowing slit separation and wavelength.

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2 years ago