Answer:
A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.
Explanation:
Hello,
A 50-mL volumetric cylinder with 0.1-mL accuracy scale should be used for this purpose since three significant figures of accuracy are required.
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Through the scientific method.
Through a hypothesis.
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Answer:
a positive charge of +1
Explanation:
The charge carried by atom depends on the number of protons and electrons present. The neutrons are not charged hence they do not contribute to the net charge of the specie.
The specie mentioned in the question has six protons and five electrons. Hence it has an excess of one positive charge hence a net charge of +1.
1) Equlibrium reaction
CH3COOH (aq) = CH3COO(-) (aq) + H(+) (aq)
2) Equilibrium constant
Keq = Ka = [CH3COO-] [H+] / [CH3COOH]
3) Equilibrium concentrations
CH3COOH CH3COO- H+
start 1.40 0 0
react x 0 0
produced 0 x x
equilibrium 1.40 - x x x
=> Ka = x * x / (1.40 - x)
Approximation: given that Ka is very small x <<< 1,40 and 1.40 - x ≈ 1.40
=> Ka ≈ x^2 / 1.40
=> x^2 ≈ 1.40Ka = 1.40 * 1.8 * 10^ - 5 = 2.52 * 10^-5
=> x ≈ √(2.52 * 10^-5) ≈ 5.02 * 10^ -3 M
4) pH = log 1 / [H+]
[H+] = x = 5.02 * 10^-3M
=> pH ≈ log (1 / 5.02 * 10^-3) ≈ 2.3
Answer: 2.3