Question

A 20 g piece of metal with specific heat 0.4 J/g.°C absorbs 3.9 kilojoules of heat,

Answer 1

Answer:

given that

....the mass of the metal is 20g(0.02kg)

....specific heat capacity(c) is 0.4J/g°C

....ΔT=??

heat(Q)=3.9KJ(3900J)

Q=mcΔT

ΔT= Q/mc

.....=3900÷(20g x 0.4J/g°C)

.....=487.5°C