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3 years ago

A 20 g piece of metal with specific heat 0.4 J/g.°C absorbs 3.9 kilojoules of heat,

Chemistry

1 answer:

Ket [755]3 years ago

8 0

Answer:

given that

....the mass of the metal is 20g(0.02kg)

....specific heat capacity(c) is 0.4J/g°C

....ΔT=??

heat(Q)=3.9KJ(3900J)

Q=mcΔT

ΔT= Q/mc

.....=3900÷(20g x 0.4J/g°C)

.....=487.5°C

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3 years ago

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learn more:

Periodic table brainly.com/question/2690837

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