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fenix001 [56]
3 years ago
14

What is the molarity of a solution prepared by dissolving 1.56 g of gaseous hcl (molar mass = 36.5 g into enough water to make 2

6.8 ml of solution?
Chemistry
1 answer:
NARA [144]3 years ago
3 0
Molar mass HCl : <span>36.5 g/mol
</span>
number of moles:

n  = mass solute / molar mass

n = 1.56 / 36.5

n =0.0427 moles

Volume in liters : 26.8 mL / 1000 => 0.0268 L

therefore:

Molarity  = moles solute / volume 

Molarity =  0.0427  / 0.0268 => 1.593 M
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Answer:

No, it is not feasible because the Gibbs free energy change is positive

Explanation:

∆Hreaction= (-602 KJ/mol) - (-348 KJ/mol) = -254 KJ/mol

∆Sreaction = (42 + 27) J/Kmol - (33 + 44) J/K = -8J/Kmol

From;

∆G = ∆H - T∆S

∆G = 254 × 10^3 J/mol - [340K × (-8 J/Kmol)]

∆G = 2.57 × 10^5 J/mol

Note that when the change in free energy is positive, a reaction is non spontaneous. Only a reaction that has a negative change in free energy is spontaneous.

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3 years ago
Determine the mass percent composition of a solution made by dissolving 40.1g of LiOH in 681g of H2O
Lapatulllka [165]
<h3>Answer:</h3>

5.89%

<h3>Explanation:</h3>

We are given;

  • Mass of the solute, LiOH as 40.1 g
  • Mass of the solvent, H₂O as 681 g

We are required to calculate the mass percent composition of solution;

  • But; How do we calculate the mass percent composition of a solution?
  • We use the formula;
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Mass Percent = (40.1 g/681 g)× 100%

                       = 5.888 %

                       = 5.89%

Therefore, the mass percent composition of the solution is 5.89%

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