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Alexxandr [17]
3 years ago
6

Consider the reaction: Na2CO3 + 2HCl → 2NaCl + CO2 + H2O. A minimum of _____ moles of sodium carbonate is needed to fully react

with 750 g of HCl
Chemistry
1 answer:
Artemon [7]3 years ago
3 0
<span>Na</span>₂<span>CO</span>₃<span> + 2 HCl  = 2 NaCl + CO</span>₂<span> + H</span>₂<span>O

106 g Na</span>₂CO₃ -------- 2 x 36.5 g HCl
<span> x g Na</span>₂CO₃ ---------- 750 g HCl
<span>
Mass of Na</span>₂CO₃ = 750 x 106 / 2 x 36.5
<span>
Mass ( Na</span>₂CO₃) = 79500 / 73
<span>
Mass = 1089.04 g

Number of moles = 1089.04 / 106 => 10.27 mols of Na</span>₂CO₃
<span>
hope this helps!


</span><span>
</span>
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olganol [36]

Answer: pH = 6.77

Explanation:

1) <u>Chemical equilibrium</u>

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2) <u>Equilibrium constant, Kw</u>

  • Kw = [H₃O⁺] × [OH⁻]
  • By stoichiometry [H₃O⁺] = [OH⁻]. Call it x
  • Kw = x²
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3)<u> pH</u>

  • pH = - log [H₃O⁺] = - log (1.709 × 10⁻⁷) = 6.77
5 0
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What is the ph of a buffer consisting of 0.200 m hc2h3o2 and 0.200 m kc2h3o2? the k a for hc2h3o2 is 1.8×10−5. view available hi
AURORKA [14]
PH = pKa + log \frac{[base]}{[Acid]}
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6 0
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Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C &amp; occupying 2.53 L. You mu
chubhunter [2.5K]

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The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

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2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

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