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Alexxandr [17]
3 years ago
6

Consider the reaction: Na2CO3 + 2HCl → 2NaCl + CO2 + H2O. A minimum of _____ moles of sodium carbonate is needed to fully react

with 750 g of HCl
Chemistry
1 answer:
Artemon [7]3 years ago
3 0
<span>Na</span>₂<span>CO</span>₃<span> + 2 HCl  = 2 NaCl + CO</span>₂<span> + H</span>₂<span>O

106 g Na</span>₂CO₃ -------- 2 x 36.5 g HCl
<span> x g Na</span>₂CO₃ ---------- 750 g HCl
<span>
Mass of Na</span>₂CO₃ = 750 x 106 / 2 x 36.5
<span>
Mass ( Na</span>₂CO₃) = 79500 / 73
<span>
Mass = 1089.04 g

Number of moles = 1089.04 / 106 => 10.27 mols of Na</span>₂CO₃
<span>
hope this helps!


</span><span>
</span>
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