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1 year ago

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Physics

2 answers:

Soloha48 [4]1 year ago

5 0

The momentum of the second ball was 15 kg.m/s.

<h3>What is inelastic collision?</h3>

In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.

In the given question,

Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.

Initial velocity of 1st ball of mass 3 kg is 1 m/s.

So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.

According to Principle of conservation of linear momentum for this inelastic collision,

Initial momentum of first ball + initial momentum of second ball = final momentum of the system

⇒ initial momentum of second ball = final momentum of the system - Initial momentum of first ball

= 18 kg.m/s - 3 kg.m/s.

= 15 kg.m/s.

Hence, initial momentum of second ball = 15 kg.m/s.

Learn more about momentum here:

brainly.com/question/24030570

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liq [111]1 year ago

5 0

Answer:

the answer is 15kgm/s

Ptotal=18 kgm/

m1v1+m2v1=18

(3kg)(1)+m2v1=18

3+m2v1=18

subtract 3

m2v1=15

because p=mv

the momentum of the second ball is 15 kgm/

Explanation:

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3 years ago

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A car is moving at 19 m/s along a curve on a horizontal plane with radius of curvature 49m.

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Answer:

$\mu =0.75$

Explanation:

<u>Frictional Force </u>

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$F_r=\mu .m.g$

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$\displaystyle \mu .m.g=m.\frac{v^2}{r}$

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$\displaystyle \mu =\frac{v^2}{rg}$

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Answer:

Explanation:

Given that,

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G = 6.67×10^−11 N⋅m²/kg²

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