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1 year ago

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Physics

2 answers:

Soloha48 [4]1 year ago

5 0

The momentum of the second ball was 15 kg.m/s.

<h3>What is inelastic collision?</h3>

In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.

In the given question,

Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.

Initial velocity of 1st ball of mass 3 kg is 1 m/s.

So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.

According to Principle of conservation of linear momentum for this inelastic collision,

Initial momentum of first ball + initial momentum of second ball = final momentum of the system

⇒ initial momentum of second ball = final momentum of the system - Initial momentum of first ball

= 18 kg.m/s - 3 kg.m/s.

= 15 kg.m/s.

Hence, initial momentum of second ball = 15 kg.m/s.

Learn more about momentum here:

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liq [111]1 year ago

5 0

Answer:

the answer is 15kgm/s

Ptotal=18 kgm/

m1v1+m2v1=18

(3kg)(1)+m2v1=18

3+m2v1=18

subtract 3

m2v1=15

because p=mv

the momentum of the second ball is 15 kgm/

Explanation:

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Travka [436]

Answer:

$0.62\:\mathrm{s}$

Explanation:

Since the universal SI unit for velocity is meters/second, let's convert ft/s to m/s:

$10\:\mathrm{ft/s}=3.048\:\mathrm{m/s}$

We can use the following kinematics equation to solve this question:

$v_f=v_i+at$

What we know:

The initial velocity, $v_i$ , is $3.048\:\mathrm{m/s}$

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Acceleration, $a$ , is acceleration due to gravity at about $9.8\:\mathrm{m/s}$

Solving for $t$ :

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3 years ago

An empty semi-truck sits on the scale of a weighing station. It is then loaded with 100 irritated pigeons. These two events then

mina [271]

Answer:

The reading in the scale is going to be the same, or if it experiences some change it would be minimum. The reason is because the truck will act as a big closed cage, therefore, when the pigeons fly, the air they move with their wings in order to keep flying, exerts the same force on the closed cage, that if they were standing on the ground.

If the truck however, allows the air flow, the weight might change, because under this scenario, the air flowing could represent less force exerted on the balance.

Explanation:

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4 years ago

A block of mass 0.254 kg is placed on top of a light, vertical spring of force constant 5 100 N/m and pushed downward so that th

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Answer:

8.86 m

Explanation:

According to the law of conservation of energy, the elastic potential energy initially stored in the spring will be converted into gravitational potential energy of the block when it is at its maximum height:

$\frac{1}{2}kx^2 = mgh$

where

k = 5100 N/m is the spring constant

x = 0.093 m is the spring compression

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g = 9.8 m/s^2 is the acceleration due to gravity

h is the maximum height of the block

Solving the equation for h, we find

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3 years ago

The box now rests on a frictionless ramp angled at 15◦ . The mover pulls up on a rope attached to the box to move it up the incl

Nataly [62]

Answer:

F = 84.61 N

Explanation:

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Lera25 [3.4K]

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4 years ago